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ZanzabumX [31]
3 years ago
11

Find the solutions to the equation below. 2x2 + 7x + 3 = 0

Mathematics
2 answers:
Tanzania [10]3 years ago
8 0

Answer: x=-1

Step-by-step explanation: 2 times 2 is 4 plus 7x plus 3. Move 4 and 3 over and you get negative 7. Divide by 7 and x=-1.

zmey [24]3 years ago
3 0

Answer:

x = -1/2 and x = -3

Step-by-step explanation:

2x² + 7x + 3 = 0

Using AC method:

2 × 3 = 6

Factors of 6 that add up to 7: 1 and 6

Divide by 2 and reduce: 1/2, 6/2 = 3/1

The factors are (2x + 1) and (x + 3)

(2x + 1) (x + 3) = 0

2x + 1 = 0

x = -1/2

x + 3 = 0

x = -3

The solutions are x = -1/2 and x = -3.

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larisa86 [58]

Answer:

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Parentheses; Exponents; Multiplication; Division; Addition; Subtraction

8 0
3 years ago
If seven pencils cost $.84 find the cost of 10 pencils
Darya [45]
Salutations!

If seven pencils cost $.84 find the cost of 10 pencils?

Lets solve this!

To solve this question, you need to first divide .84 ÷ 7 which gives you the answer 0.12. Then multiply 0.12 with 10 which gives you the cost of 10 pencils. 0.12 is the cost of only one pencil.

Lets forms this into statements ---

Cost of 7 pencils = $ .84

Cost of 1 pencil = $ 0.12

Cost of 10 pencil equals = .84 ÷ 7 = 0.12

                                      = 0.12 × 10 = 1.2

Cost of 10 pencils is $1.2

Hope I helped (:

Have a great day!
3 0
3 years ago
Read 2 more answers
Show all of your work, even though the question may not explicitly remind you to do so. Clearly label any functions, graphs, tab
natta225 [31]

Answer:

  (a) at t=2, the particle is moving toward the origin

  (b) a(t) = 70(8 -9t^2)/(3t^2 +8)^3; a(2) = -0.245

  (c) the particle approaches x = 1/3 as t gets large

Step-by-step explanation:

(a) The function x(t) is negative for -3 < t < 3, so at t = 2, the particle is to the left of the origin.

The velocity of the particle is given by the derivative of the position function:

  x'(t)=\dfrac{(3t^2+8)(2t)-(t^2-9)(6t)}{(3t^2+8)^2}=\dfrac{70t}{(3t^2+8)^2}

Then, at t=2, the expression is positive, indicating the particle is moving toward the origin.

__

(b) The acceleration is the derivative of the velocity, so is ...

  a(t)=\dfrac{70(3t^2+8)^2-(70t)(12t)(3t^2+8)}{(3t^2+8)^4}=\dfrac{70(3t^2+8-12t^2)}{(3t^2+8)^3}\\\\\boxed{a(t)=\dfrac{70(8-9t^2)}{(3t^2+8)^3}}

Then at t=2, the acceleration is ...

  a(2) = 70(8 -9·4)/(3·4+8)^3 = 70(-28)/8000

  a(2) = -0.245

__

(c) As t gets large, the value of x(t) approaches t^2/(3t^2) = 1/3.

7 0
4 years ago
Which value of x would make this equation true? 4x-10=18
garik1379 [7]
1) move the 10 over to the other side which would give you 28.
2) divide by 4 to get x by itself.

ANSWER: 7
4 0
3 years ago
Read 2 more answers
The table shows information about all students doing GCSE's at a school.
PilotLPTM [1.2K]

Answer:

it's 3/5

Step-by-step explanation:

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6 0
4 years ago
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