Answer:
1.5000000000000000000
Step-by-step explanation:
Notice that
11/12 = 1/6 + 3/4
so that
tan(11π/12) = tan(π/6 + 3π/4)
Then recalling that
sin(x + y) = sin(x) cos(y) + cos(x) sin(y)
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
⇒ tan(x + y) = (tan(x) + tan(y))/(1 - tan(x) tan(y))
it follows that
tan(11π/12) = (tan(π/6) + tan(3π/4))/(1 - tan(π/6) tan(3π/4))
tan(11π/12) = (1/√3 - 1)/(1 + 1/√3)
tan(11π/12) = (1 - √3)/(√3 + 1)
tan(11π/12) = - (√3 - 1)²/((√3 + 1) (√3 - 1))
tan(11π/12) = - (4 - 2√3)/2
tan(11π/12) = - (2 - √3) … … … [A]
Step-by-step explanation:
eggfdddfgggfseeedhhggh
Well, let's see. The problem gave you an ordered pair. In other words, you have an 'x' and a 'y' coordinate. All you need to do is put them into the equation.
Step-by-step explanation:
This means that instead of --
-3x - 3y = 125 + 5y = -20
We would have:
-3(-5)-3(-5) = 125(-5) + 5(-5) = -20
From here, you just simplify it into:
30 = -650 = -20
Since the values are not the same, the ANSWER is NO. The ordered pair does not satisfy the following system of equations.
