Answer:
In geometry, the area enclosed by a circle of radius r is πr2. Here the Greek letter π represents a constant, approximately equal to 3.14159, which is equal to the ratio of the circumference of any circle to its diameter.
Explanation:
Answer:
Follows are the method definition to this question:
void printArray(int arrayToPrint[], int arraySize) //defining a method printArray that accepts two array in its parameters
{
for (int j = 0; j < arraySize; j++)//defining for loop print Serial numbers
{
Serial.print("[");//use print method to print square bracket
Serial.print(j);//use print method to print Serial numbers
Serial.print("]: ");//use print method to print square bracket
Serial.println(arrayToPrint[j]);//printing array value
}
}
Explanation:
In the above code, a method "printArray" is declared that holds two arrays "arrayToPrint and arraySize" as a parameter, and inside the method is used for loop to print the values.
In the loop, first, it uses the square bracket to print the serial number and in the last step, it prints array values.
I believe that the three procedures are...
1. Sub - Standard sub routine
2. Function - a routine that returns an answer
3. Property - reserved for <span> Class Modules</span>
<span>Hope this helps, please mark brainliest!</span>
