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3 years ago

Help me answer this please!!

Mathematics

2 answers:

Masja [62]3 years ago

5 0

Answer:

Step-by-step explanation:

Alyssa will correctly label the numbers 48.8 48 48.09 and 48 on the number line below Which number will be located closest to 48

yarga [219]3 years ago

3 0

Answer:

the answer is (6*10^6)

Step-by-step explanation:

Multiply the beginning numbers and add the exponents.

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Determine if 0.747447444744447444447... is rational or irrational and give reason for your answer.

Ugo [173]

Answer:

Irrational

Step-by-step explanation:

Digits that go on forever are irrational if I remeber correctly.

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4 years ago

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Function f is shown on the graph

Natali [406]

Answer:

Option A, (-4, -1)

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3 years ago

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Mazyrski [523]

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3 years ago

Hii i’ll give brainliest please help thanks :)

Juliette [100K]

Answer:

Step-by-step explanation:

The mean (average) of a data set is found by adding all numbers in the data set and then dividing by the number of values in the set. The median is the middle value when a data set is ordered from least to greatest.

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3 years ago

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

Put $(x,y)=(1,1)$

$\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9$

This is true.

So, the point $(1,1)$ satisfies the equation $\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

So, point H is $(1,1)$ .

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3 years ago