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Bogdan [553]
3 years ago
6

A. Identify the relationship between the two

Mathematics
1 answer:
kykrilka [37]3 years ago
7 0

Answer:

a - Mutual

b - (x+21)+(2x+3)=90

c - 3x +24 =90

3x=90-24

3x=66

X=22

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The product of 9 and number (x) is 88. Which equation shows this relationship?
Digiron [165]
This equation is
9*x =88
5 0
3 years ago
The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

4 0
3 years ago
Colton has a stone paperweight composed of a triangular pyramid on top of a triangular prism with the dimensions shown below. Us
Eva8 [605]

The area of the base would be found using the area of a triangle formula which is 1/2 x base x height.

The base and height are the two sides perpendicular to each other, which are both 5 inches.

The area of the base = 1/2 x 5 x 5 = 12.5 square inches.

The volume of the triangular prism is the area of the base times the height, which is 4 inches.

Volume of the triangular prism is 12.5 x 4 = 50 cubic inches.

Volume of the triangular prism is 1/3 x area of base x height, which is 7:

Volume of the triangular prism = 1/3 x 12.5 x 7 = 29.17 cubic inches.

Total volume = 29.17 + 50 = 79.17 cubic inches.

3 0
3 years ago
A soccer ball made of leather 1/81/8 in thick has an inner diameter of 8.58.5 in . Use the formula V=(4/3)πr3V=(4/3)πr3 to calcu
Sphinxa [80]
1/8 inch thick
inner diameter of 8.5

volume shell=volume total-volume shell


1/8=0.125

diameter/2=radius
radius inner=8.5/2=4.25
radiustotal=inner+outer=4.25+0.125=4.375


so

Vouter-Vinner=(4/3)pi4.375³-(4/3)pi4.25³
Vshell=(4/3)(pi)(4.375³-4.25)
Vshell=(4/3)(pi)(83.740234375-76.765625)
Vshell=(4/3)(pi)(6.974609375)
Vshell=9.299479166666666666666pi cubic inches
Vshell≈16.433536180619 cubic inches
6 0
3 years ago
Read 2 more answers
On a coordinate plane, a line is drawn from point C to point D. Point C is at (negative 1, 4) and point D is at (2, 0). Point C
skelet666 [1.2K]

Answer:

distance = 5 units

Step-by-step explanation:

In order to solve this problem we can start by plotting the two points you were provided with (see attached picture). This will help us visualize the problem better.

Now, we need to find the distance between those two points, so in order to do so we can use the distance formula:

distance = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

in this case the x's and y's are given by the given points, since they are written as ordere pairs. And ordered pairs are written in the form (x,y). So for Point C:

C=(-1,4)

x_{1}=-1

y_{1}=4

and for point D

D=(2.0)

x_{2}=2

y_{2}=0

so we can now use those values in our distance formula so we get:

d=\sqrt{(2-(-1))^{2}+(0-4)^{2}}

d=\sqrt{(3)^{2}+(-4)^{2}}

d=\sqrt{9+16}

d=\sqrt{25}

d=5 units.

3 0
3 years ago
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