(6p-6/p)•((9p^2)/2p-2)
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The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:
where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:
Hence, the half life of the sample of phosphorus-32 is
Answer: x=-6
Step-by-step explanation:
Let's solve your equation step-by-step.
2(9−x)=3(x+16)
Step 1: Simplify both sides of the equation by distribution
Step 2: Subtract 3x from both sides.
Step 3: Subtract 18 from both sides.
Step 4: Divide both sides by -5.