(6p-6/p)•((9p^2)/2p-2)
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Answer:
please see explanation
Step-by-step explanation:
look at the photo
According to the fundamental theorem of algebra, <span>every polynomial of degree n has n complex zeroes.
Part A:
Given
Thus, the given polynomial is of degree 5 and hence has 5 omplrex roots.
Part B:
Given
Thus, the polynomial is of degree 4 and hence has 4 complex roots.
Part C:
Given
Thus, the given polynomial is of degree 6 and hence has 6 complex roots.
Part D:
Given
</span><span>Thus, the given polynomial is of degree 7 and hence has 7 complex roots.</span>
Part E:
Given
Thus, the given polynomial is of degree 5 and hence has 5 complex roots.
Part A:
Given
Thus, the given polynomial is of degree 5 and hence has 5 omplrex roots.
Part B:
Given
Thus, the polynomial is of degree 4 and hence has 4 complex roots.
Part C:
Given
Thus, the given polynomial is of degree 6 and hence has 6 complex roots.
Part D:
Given
</span><span>Thus, the given polynomial is of degree 7 and hence has 7 complex roots.</span>
Part E:
Given
Thus, the given polynomial is of degree 5 and hence has 5 complex roots.