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777dan777 [17]
3 years ago
14

Ok I need help!!

Mathematics
1 answer:
dolphi86 [110]3 years ago
7 0

Answer:

she would be under $13

Step-by-step explanation:

1.50+1= 2.50+9.28= 11.78 leaving her with a remaining balance off $1.22

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How do i solve for x​
BARSIC [14]

Answer: x=60°

Step-by-step explanation:

The angles of an equilateral triangle are ALWAYS 60° You can tell its an equilateral triangle because of the lines through each side.

3 0
3 years ago
Van found the change in a scale factor. His work is shown below. What error did Ivan make?
8090 [49]

Answer:

Ivan wrote the ratio incorrectly. The ratio should be written as the old length to the new length, so it should be 35

10

, which reduces to 7

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. When going from larger to smaller dimensions, the change in the scale factor is a ratio that looks like an improper fraction, with a larger number in the numerator and a smaller number in the denominator.

Step-by-step explanation:

4 0
3 years ago
What is 3/4÷1/2? Please it is important I get 100$ I’ll split
laiz [17]

Answer:

1.5

Step-by-step explanation:

3 0
3 years ago
Alabama Instruments Company has set up a production line to manufacture a new calculator. The rate of production of these calcul
kondaur [170]

Answer:

Calculators from the beginning of the third week to the end of the fourth week = 4048.

Step-by-step explanation:

We know that the rate of production of these calculators after t weeks is given by

\frac{dx}{dt} =5000(1-\frac{100}{(t+10)^{2}})

To find the number of calculators that have been produced in a period, we need to take the integral of the function above; the desired time is t=2 (beginning of third week) to t=4 (end of the fourth week). Therefore, the number of calculators produced in the given time is

\int\limits^4_2 {\frac{dx}{dt} } \, dt = \int\limits^4_2 {5000(1-\frac{100}{(t+10)^{2} }) } \, dt

Substitute t+10=u and dt=du, observe that the limits of integration will change

\int\limits^4_2 {\frac{dx}{dt} } \, dt => \int\limits^{14}_{12} {\frac{du}{dt} } \, dt

5000\int\limits^{14}_{12} { 1-\frac{100}{u^{2} } } \, du

5000(u+100u^{-1})\left \{ {{14} \atop {12}}\right.\\5000(2+\frac{100}{14}-\frac{100}{12} )\\4047.62 ≈ 4048

4 0
3 years ago
Hello! Help me in my question.​
erastovalidia [21]

Answer:

what is your questions?

6 0
3 years ago
Read 2 more answers
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