Ask question

Ask question

All categories

3 years ago

6

The Li Fruit Co. needs to ship an order of 3,600 bananas. If each box can hold 600 bananas, how many boxes will the company need

?

1 answer:

malfutka [58]3 years ago

5 0

Answer:

The Company will only need 6 boxes.

Step-by-step explanation:

600*6 = 3,600

You might be interested in

The number is a multiple of 5.<br> 4<br> 3<br> 6<br> 1 =

My name is Ann [436]

Answer:

you can multiply nothing by 5 to get you any of those numbers

8 0

3 years ago

Marcy got tickets to see the Backstreet Boys in Las Vegas. She wanted to sit in the middle seat of row 1 section 205, which is d

svlad2 [7]

No, False. All seats in row 1 are same viewing angle. They are inscribed angles measuring 90 degrees. All the seats on row 1 will have the exact same viewing angle because they form a semi-circle around the stage. these would be inscribed angles that have the endpoints of the stage. They would all be 90-degree agles because the stage creates a semicircle and the endpoints of the stage are all the same.

3 0

3 years ago

H(x)=-x-1h(x)=−x−1, find h(-2)h(−2)

Karo-lina-s [1.5K]

$▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪$

Given function :

$h(x) = - x - 1$

we have to find h(-2) :

$h( - 2) = - ( - 2) - 1$

$h( - 2) = 2 - 1$

$h ( - 2) = 1$

4 0

3 years ago

yarga [219]

Answer:

Step-by-step explanation:

4.7y

8 0

4 years ago

Pineapple Corporation (PC) maintains that their cans have always contained an average of 12 ounces of fruit. The production grou

krok68 [10]

Answer:

We accept the null hypothesis, that is, that the mean weight of the cans is still of 12 ounces of fruit.

Step-by-step explanation:

Pineapple Corporation (PC) maintains that their cans have always contained an average of 12 ounces of fruit.

This means that the null hypothesis is: $H_0: \mu = 12$

The production group believes that the mean weight has changed.

This means that the alternate hypothesis is:

$H_a: \mu \neq 12$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

12 is tested at the null hypothesis:

This means that $\mu = 12$

They take a sample of 15 cans and find a sample mean of 12.05 ounces and a sample standard deviation of .08 ounces.

This means, respectibely, that $n = 15, X = 12.05, \sigma = 0.08$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{12.05 - 12}{\frac{0.08}{\sqrt{15}}}$

$z = 2.42$

Pvalue of the test:

We are testing if the mean is different from a value, which means that the pvalue is 2 multiplied by 1 subtracted by the pvalue of z = 2.42.

Looking at the z-table, z = 2.42 has a pvalue of 0.9922

1 - 0.9922 = 0.0078

2*0.0078 = 0.0156

What conclusion can we make from the appropriate hypothesis test at the .01 level of significance?

0.0156 > 0.01. This means that at the 0.01 level, we accept the null hypothesis, that is, that the mean weight of the cans is still of 12 ounces of fruit.

6 0

3 years ago