Answer:
56% ≤ p ≤ 70%
Step-by-step explanation:
Given the following :
Predicted % of votes to win for candidate A= 63%
Margin of Error in prediction = ±7%
Which inequality represents the predicted possible percent of votes, x, for candidate A?
Let the interval = p
Hence,
|p - prediction| = margin of error
|p - 63%| = ±7%
Hence,
Upper boundary : p = +7% + 63% = 70%
Lower boundary : p = - 7% + 63% = 56%
Hence,
Lower boundary ≤ p ≤ upper boundary
56% ≤ p ≤ 70%
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
The answer is D thirteen multiplied by h is 13h. The word "is" typically means = so 13h=104. to solve for this you want to isolate the h on one side of the equation. to do this we need to get rid of the 13 and move it on the other side of the equation. the new equation is h=104÷13. So, h=8. Hope this helps!
C because you got to find the like term term