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djyliett [7]
3 years ago
8

The point-slope form of a line that has a slope of –2 and passes through point (5, –2) is shown below.

Mathematics
1 answer:
krek1111 [17]3 years ago
3 0
Answer: y= -2x+8

Step by step:

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Centroid of triangle with vertices (0,0) ,(3,0) & (0,-3) is……. [ ]
Firdavs [7]

Answer:

b

Step-by-step explanation:

centroid

x=(x1+x2+x3)/3=(0+3+0)/3=3/3=1

y=(y1+y2+y3)/3=(0+0-3)/3=-3/3=-1

centroid =(1,-1)

3 0
3 years ago
Read 2 more answers
Find the derivative of the function at P 0 in the direction of A. ​f(x,y,z) = 3 e^x cos(yz)​, P0 (0, 0, 0), A = - i + 2 j + 3k
Alik [6]

The derivative of f(x,y,z) at a point p_0=(x_0,y_0,z_0) in the direction of a vector \vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k is

\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}

We have

f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k

and

\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}

Then the derivative at p_0 in the direction of \vec a is

3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}

3 0
4 years ago
What would be the orientation of the figure out after a translation of eight units to the right and three units up
BaLLatris [955]
Whats the starting point
8 0
3 years ago
Please answer with explanation
Ipatiy [6.2K]

<u>Answer:</u>

a direct variation is a relation that is of the form <u>y = mx</u>

  • example of a direct variation: y = 2x

a partial variation is is a relation that is of the form <u>y = mx+b</u>

  • example of a partial variation: y = 2x + 1

  • a non-linear function doesn't have a constant rate of change
  • the graph for a non-linear relationship is curved
  • a non-linear curve may show a positive or a negative relationship
5 0
3 years ago
Find the value of each variable, please explain.
Airida [17]

Answer:

x=67

y=113

z=50

Step-by-step explanation:

x=180-28-85=67

y=180-67=113

z=17+113=50

4 0
3 years ago
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