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DochEvi [55]
2 years ago
8

Simplify. Use the ^ to show an exponent and the / for the fraction bar.

Mathematics
1 answer:
patriot [66]2 years ago
4 0
X exponent 3 / 2y

hope this helps!
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What is the equation for the line that passes through (3, 2) and has a slope<br> equal to 1/3
lana66690 [7]

Answer:

y=1/3x+1

Step-by-step explanation:

6 0
2 years ago
Helpppp plz??????????????
professor190 [17]

Answer:

6/54 or 1/9

Step-by-step explanation:

6/54 reduces to 1/9

hope this helps

8 0
2 years ago
Find the area of a circle having a circumference of 231 pi units. Round to the nearest tenth.
loris [4]
Do you by any chance have a diagram of the circle or the r value?
7 0
2 years ago
A problem on a multiple-choice quiz is answered correctly with probability 0.9 if a student is prepared. An unprepared student g
lions [1.4K]

Answer:

0.08475

Step-by-step explanation:

The question above is a application of conditional probability.

The formula to use is Baye's Theorem for conditional probability.

From the above question we have the following information:

Probability of answering correctly when prepared = 0.9

Probability of not answering correctly when prepared = 1 - 0.9 = 0.1

Probability of choosing the right answer = 1/4 = 0.25

Probability of choosing the wrong answer = 1 - 0.25 = 0.75

Number of students that prepare for the quiz = 75% = 0.75

Therefore number of students that did not prepare for the quiz = 1 - 0.75

= 0.25

Hence,

The probability of not preparing but choosing the correct answer =

P[ not prepared | correct answer ]

Is calculated as :

P[ not prepared | correct answer ] =

(0.25 × 0.25)/(0.25 × 0.25) + (0.25 × 0.9)

= 0.08475

Therefore, the chance that Mr X did not prepare for the quiz but he gives the right answer = 0.08475

3 0
3 years ago
The mean amount of money spent on lunch per week for a sample of 100 students is $21. If the margin of error for the population
Digiron [165]

From the given mean and margin of error, the 99% confidence interval for the mean amount of money spent on lunch per week for all students is:

[$19.5, $22.5].

<h3>How to calculate a confidence interval given the sample mean and the margin of error?</h3>

The confidence interval is given by the sample mean plus/minus the margin of error, hence:

  • The lower bound is the sample mean subtracted by the margin of error.
  • The upper bound is the sample mean added to the margin of error.

For this problem, we have that:

  • The sample mean is of $21.
  • The margin of error is of $1.50.

Hence the bounds are given as follows:

  • Lower bound: 21 - 1.50 = $19.50.
  • Upper bound: 21 + 1.50 = $22.50.

Hence the interval is [$19.50, $22.50].

More can be learned about confidence intervals at brainly.com/question/25890103

#SPJ1

7 0
9 months ago
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