The first bus route is 4 miles from school. How many yards is the first bus stop from school?
2 answers:
You might be interested in
Using the normal distribution, it is found that:
a) Her waist is at the 2.74th percentile.
b) 99.86% of female soldiers requires custom uniform pants.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
.
Item a:
The percentile is the <u>p-value of Z when X = 26.1,</u> hence:
Z = -1.92
Z = -1.92 has a p-value 0.0274 = 2.74th percentile.
Item b:
The proportion is the <u>p-value of Z when X = 32 subtracted by the p-value of Z when X = 24</u>, hence:
X = 32:
Z = 3.
Z = 3 has a p-value 0.9987.
X = 24:
Z = -3.67.
Z = -3.67 has a p-value 0.0001.
0.9987 - 0.0001 = 0.9986 = 99.86% of female soldiers requires custom uniform pants.
More can be learned about the normal distribution at brainly.com/question/25800303
#SPJ1
Answer:
Approximate probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is less than 0.0005% .
Step-by-step explanation:
We are given that let X be the number that do some or all of their banking on the Internet.
Also; Mean, = 310/1000 or 0.31 and Standard deviation,
= 14.63/1000 = 0.01463 .
We know that Z = ~ N(0,1)
Probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is given by P(X <= 130/1000);
P(X <=0.13) = P( <=
) = P(Z <= -12.303) = P(Z > 12.303)
Since this value is not represented in the z table as the value is very high and z table is limited to x = 4.4172.
So, after seeing the table we can say that this probability is approximately less than 0.0005% .