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Alex
3 years ago
12

A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu

dget for the corporate team-building event is $31?
Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

There can be at most 12 attendees in a corporate team-building event.

Step-by-step explanation:

Let x denotes number of attendees in a corporate team-building event.

Fixed cost = $19

Cost charged per attendee = $1

Budget for the corporate team-building event = $31

Therefore,

19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12

So, there can be at most 12 attendees in a corporate team-building event.

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A local fair has an entrance fee of $10. Each ride costs $1.25.
Archy [21]

Answer:

Step-by-step explanation:

6 0
3 years ago
joe and james are selling pies for a school fundraiser. Customers can buy blueberry pies and blackberry pies. Joe sold 5 blueber
dimulka [17.4K]
This is a system of equations problem.

Blueberry = X, blackberry = Y

Joe:
5x + 10y = 135

James:
x + 9y = 104

Let’s isolate x from James’ equation.
x = 104 - 9y

Now substitute that into the first equation.
5(104 - 9y) + 10y = 135

520 - 45y + 10y = 135

-35y = -385

y = -385/-35. The negatives cancel out, leaving us with $11 for blackberries.

Now we can substitute that value into James’s equation.

x + 9(11) = 104

x = 104 - 99

x = $5

Final answer: Blueberry pies cost $5, blackberry pies cost $11.
3 0
2 years ago
3/4 : 12 = 3n solve using cross method
ANTONII [103]

Answer:

N = 1/48

Step-by-step explanation:

In pic

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7 0
2 years ago
What is the solution to the system of equations? Use the substitution method.
ludmilkaskok [199]
The answer is A. (3,-1/2)
3 0
2 years ago
Which equation is equivalent to √x^2+81 = x+10
jeka57 [31]

Keywords:

<em>equation, operations, equivalent, binomial, square root </em>

For this case we have an equation in which we must apply operations to rewrite it in an equivalent way. We must start by raising both sides of the equation to the square. Thus, we eliminate the square root of the left side of equality and finally solve the binomial of the right side of equality.

So we have:

\sqrt {x ^ 2 + 81} = x + 10\\(\sqrt {x ^ 2 + 81}) ^ 2 = (x + 10) ^ 2\\x ^ 2 + 81 = (x + 10) ^ 2

By definition:(a + b) ^ 2 = a ^ 2 + 2ab + b ^ 2

x ^ 2 + 81 = x ^ 2 + 2 (x) (10) + (10) ^ 2\\x ^ 2 + 81 = x ^ 2 + 20x +100

Thus, x ^ 2 + 81 = x ^ 2 + 20x +100 is equivalent to \sqrt {x ^ 2 + 81} = x + 10

Answer:

x ^ 2 + 81 = x ^ 2 + 20x +100

Option D

4 0
3 years ago
Read 2 more answers
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