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Alex
3 years ago
12

A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu

dget for the corporate team-building event is $31?
Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

There can be at most 12 attendees in a corporate team-building event.

Step-by-step explanation:

Let x denotes number of attendees in a corporate team-building event.

Fixed cost = $19

Cost charged per attendee = $1

Budget for the corporate team-building event = $31

Therefore,

19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12

So, there can be at most 12 attendees in a corporate team-building event.

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The base of an isosceles triangle is one and a half times the length of the other two sides.A smaller triangle has a perimeter t
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Let the two equal sides of an isosceles triangle = x

Therefore, length of the base = (1\frac{1}{2})x

Perimeter of this isosceles triangle = x + x + (1\frac{1}{2})x

                                                          = 2x + (1+\frac{1}{2})x

                                                          = 2x + x + \frac{x}{2}

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Since, smaller triangle has a perimeter that is half the perimeter of the larger triangle,

Length of each corresponding side of smaller triangle will be half of the larger triangle.

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Perimeter of the smaller triangle = \frac{x}{2}+\frac{x}{2}+(1\frac{1}{2})\frac{x}{2}

                                                      = x + \frac{x}{2}+\frac{x}{4}

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Therefore, expression that represents the perimeter of the smaller triangle is (1.75x)        

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