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charle [14.2K]
3 years ago
11

What is the value of the expression?

Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0

100 - 81 /81

100 -1

99t

marm me brainliesy

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-4 + 4 <br> Same signs? <br> Different sign?<br> Add/Subtract?
marin [14]

Answer:

Step-by-step explanation:

-4 is negative 4 witch is less then 4. -4 +4 =0

4 0
3 years ago
Read 2 more answers
Would like this problem broken down step by step thanks!
antiseptic1488 [7]

Answer:

m=12

Explanation:

Given any quadratic function, y=ax²+bx+c.

We can determine the nature of the roots of such quadratic function by examining the discriminant, D where:

D=b^2-4ac

• If D>0, the roots are real and unequal.

,

• If D=0, the roots are real and equal.

,

• If D<0, the roots are complex.

In our given equation:

\begin{gathered} y=18x^2+mx+2 \\ a=18,b=m,c=2 \end{gathered}

For the function to have exactly one zero, the value of D=0.

\begin{gathered} D=b^2-4ac=m^2-4(18)(2)=m^2-144 \\ D=0\implies m^2-144=0 \\ Add\text{ 144 to both sides.} \\ m^2=144 \\ Take\text{ the square root of both sides} \\ \sqrt{m^2}=\sqrt{144} \\ m=12 \end{gathered}

The value of m for which the function will have one zero is 12.

4 0
1 year ago
A particle starts at the point P=(−1,1,3)P=(−1,1,3) and moves along a straight line toward Q=(−4,4,5)Q=(−4,4,5) at a speed of 7
zvonat [6]

Answer: (-1,1,-3) + 7 x t x (3,-2,-8)/\sqrt{77} \\

Step-by-step explanation:

The parametric vector equation for the position of particle is given as:

We have P= (-1,1-3)

Q= (-4,4,5)

So PQ vector= (-1+4,1-3, -3-5)

PQ = (3,-2,-8)

Magnitude of this vector= \sqrt{(3)^2+(-2)^2+(-8)^2}

Magnitude= \sqrt{77} \\

So unit vector= (3, -2, -8)/\sqrt{77} \\

Now the equation is as:

P + 7 x t x unit vector = (-1,1,-3) + 7 x t x (3,-2,-8)/\sqrt{77} \\

5 0
3 years ago
Issouf claims that the scale factor is 1/2. which statement about his claim is correct?
love history [14]

Answer:

The correct option is D.

Step-by-step explanation:

It is given that Issouf claims that the scale factor is 1/2.

From the given figure it is clear that

CB'=C'B'=2

B'B=6

CB=CB'+B'B=2+4=6

The scale factor of a figure is

k=\frac{\text{Length of any side of image}}{\text{Length of corresponding side of preimage}}

k=\frac{C'B'}{CB}

k=\frac{2}{6}

k=\frac{1}{3}

The scale factor is 1/3 because CB is actually 2 + 4 = 6.

Therefore the correct option is D.

4 0
3 years ago
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Based on the diagram below, what is the measure of arc DC ?
emmainna [20.7K]

Given:

A diagram of a circle O, arc(AB)=y^\circ, arc(CD)=(80+y)^\circ.

To find:

The measure of arc DC.

Solution:

According to the angle of intersecting chords theorem:

Angle at intersection of chords = Half of the sum of intercepted arcs.

Let \theta be the angle between the intersection of chords AC and BD.

\theta +112^\circ=180^\circ      (Linear pair)

\theta =180^\circ-112^\circ

\theta =68^\circ

Using the angle of intersecting chords theorem, we get

\theta=\dfrac{arc(AB)+arc(CD)}{2}

68^\circ =\dfrac{y^\circ+(80+y)^\circ}{2}

136^\circ =(80+2y)^\circ

On simplification, we get

136=80+2y

136-80=2y

56=2y

Divide both sides by 2.

28=y

Now,

arc(DC)=(80+y)^\circ

arc(DC)=(80+28)^\circ

arc(DC)=108^\circ

Therefore, the correct option is C.

5 0
3 years ago
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