I'm assuming you're referring to problem 6. You are asked to find the number of x intercepts or roots, which is another term for "zero". I prefer the term root or x intercept as "zero" seems misleading. Anyways, all we do is count the number of times the graph crosses the x axis. This happens 4 times as shown in the attached image below. I have marked these points in red. The graph can directly cross over the x axis, or it can touch the x axis and then bounce back. Either way, it is considered an x intercept.
<h3>Answer: there are 4 x intercepts (or 4 roots)</h3>
Answer:
8 and 19
Step-by-step explanation:
To some this, let's first list all the factors of 152. They are;
1, 2, 4, 8, 19, 38, 76, 152.
Now, let's arrange them to reflect being multiplied to get 152.
Thus;
1 × 152 = 152
2 × 76 = 152
4 × 38 = 152
8 × 19 = 152
Also, let's do the same for their sum;
1 + 152 = 153
2 + 76 = 78
4 + 38 = 42
8 + 19 = 27
Looking at the figures above, the ones that their product is 152 but have the least sum are 8 and 19
Answer:
1) -4 2)-3 3) -2 4) -1 5) 0
Step-by-step explanation:
it would be the third one, 2/3
Answer:
1. A = 2x; P = 4x+2. A = 4; P = 10.
2. A = y² +2; P = 4y +2. A = 27; P = 22.
Step-by-step explanation:
1. The area is the sum of the marked areas of each of the tiles:
A = x + x
A = 2x
__
The perimeter is the sum of the outside edge dimensions of the tiles. Working clockwise from the upper left corner, the sum of exposed edge lengths is ...
P = 1 + (x-1) + x + 1 + (x+1) + x
P = 4x +2
__
When x=2, these values become ...
A = 2·2 = 4 . . . . square units
P = 4·2+2 = 10 . . . . units
_____
2. Again, the area is the sum of the marked areas:
A = y² + 1 + 1
A = y² +2
__
The edge dimension of the square y² tile is presumed to be y, so the perimeter (starting from upper left) is ...
P = y +(y-2) +1 +2 +(y+1) +y
P = 4y +2
__
When y=5, these values become ...
A = 5² +2 = 27 . . . . square units
P = 4·5 +2 = 22 . . . . units
