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3 years ago

Please help me with this, I only have a few more questions and I'll be posting them on my page for help

Mathematics

1 answer:

Irina18 [472]3 years ago

7 0

Answer:

B) 450

Step-by-step explanation:

You use the greater amount minus the lesser amount, times 30 minutes.

55-40=15

15 x 30=150

Hope I helped!

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Write a division that represents the question: how many 3/8s are in 5/4?

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Answer:

Think your answer is 3 1/4

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3 years ago

Find f(-2) if f(x) = 2x + 1.

mash [69]

Answer:

-3

Step-by-step explanation:

f(x)=2x+1

f(-2)=2(-2)+1=-4+1=-3

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2 years ago

Given h(t)=-2(t+5)^2+4, find h(-8)

alexandr402 [8]

Substitute -8 for t in h(t)=-2(t+5)^2+4:

h(-8) = -2(-8+5)^2 + 4 = -2(-3)^2 + 4 = -2(9) + 4 = -18 + 4

h(-8) = -18 + 4 = -14 (answer)

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3 years ago

Read 2 more answers

Someone, please help me with this. Correct answers get brainiest

Phantasy [73]

Answer:

-3

sqrt(9)

-sqrt(9)

Step-by-step explanation:

What number multiplied by itself will give you 9

3*3 =9

-3*-3 =9

sqrt(9) * sqrt(9) = sqrt(81) = 9

-sqrt(9) * -sqrt(9) = + sqrt(81) =9

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3 years ago

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An certain brand of upright freezer is available in three different rated capacities: 16 ft3, 18 ft3, and 20 ft3. Let X = the ra

ruslelena [56]

Answer:

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

$E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6=349.2$

$V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24$

The expected price paid by the next customer to buy a freezer is $466

Step-by-step explanation:

From the information given we know the probability mass function (pmf) of random variable X.

$\left|\begin{array}{c|ccc}x&16&18&20\\p(x)&0.3&0.1&0.6\end{array}\right|$

Point a:

The Expected value or the mean value of X with set of possible values D, denoted by E(X) or μ is

$E(X) = $\sum_{x\in D} x\cdot p(x)$

Therefore

$E(X)=16\cdot 0.3+18\cdot 0.1+20\cdot 0.6=18.6$

If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by E[h(X)] is computed by

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)$

So $h(X) = X^2$ and

$E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2$

The variance of X, denoted by V(X), is

$V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2$

Therefore

$V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24$

Point b:

We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:

From the rules of expected value this proposition is true:

$E(aX+b)=a\cdot E(x)+b$

We have a = 60, b = -650, and E(X) = 18.6. Therefore

The expected price paid by the next customer is

$60\cdot E(X)-650=60\cdot 18.6-650=466$

4 0

3 years ago