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12345 [234]
3 years ago
14

Please help me with this, I only have a few more questions and I'll be posting them on my page for help

Mathematics
1 answer:
Irina18 [472]3 years ago
7 0

Answer:

B) 450

Step-by-step explanation:

You use the greater amount minus the lesser amount, times 30 minutes.

55-40=15

15 x 30=150

Hope I helped!

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Determine whether the triangles can be proved similar. If they are similar, write a similarity statement. If they are not simila
Ierofanga [76]

Answer: \triangle XYZ \sim \triangle GFH by AA.

Step-by-step explanation:

Finding the third angle in triangle XYZ,

m\angle YXZ=180^{\circ}-77^{\circ}-48^{\circ}=55^{\circ},

Thus, \triangle XYZ \sim \triangle GFH by AA.

3 0
2 years ago
1.4 has 2 significant digits as a result of which one?
dimaraw [331]

Answer:

1 And 3

Step-by-step explanation:

3 0
3 years ago
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What number is five million eight thousand four hundred five
Eddi Din [679]

Answer:

This number is 5008405

Step-by-step explanation:

five million = 5000000

eight thousand = 8000

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5 0
2 years ago
Von buys a bag of 34 Dog treats he gives his puppy 3 treat a day.How many days will the bag of dog treats last?
makkiz [27]

Answer:

11 days with one treat left over. Or 11.3

Step-by-step explanation:

5 0
3 years ago
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Find the equation for the circle with a diameter whose endpoints are (5,-3) and (2,1).
Natasha_Volkova [10]

Answer:

Step-by-step explanation:

To write an equation for a circle, we need to find the center and the radius.  We need to find the distance between the two endpoints to find the radius.  To do that, use the distance formula:

d = √(2 - 5)² + (1 + 3)²

√(-3)² + (4)²

√9 + 16 = √25 = 5

If the diameter is 5, the radius is 2.5

Now we need to find the center/midpoint.  Use the midpoint formula:

(5 + 2)/2, (-3 + 1)/2

7/2, -2/2

(3.5, -1)

Now that we have the center and the radius, we can make our equation.  Remember that the equation of a circle is: (x - x of center)² + (y - y of center) = radius²

(x - 3.5)² + (y + 1)² = 6.25

Hope this helps

5 0
3 years ago
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