Write a division that represents the question: how many 3/8s are in 5/4?

Which two steps should be used first in solving the system of equations

Inessa05 [86]

Answer:

The value of x , y using substitution method is 2 , 5

Step-by-step explanation:

Given as :

The two linear equation as

6 y - 4 x = 22 .......1

y + 2 x = 9

Let y = 9 - 2 x .......2

Now, using substitution method

Substitute the value of y from eq 2 into eq 1

i.e 6 × (9 - 2 x) - 4 x = 22

Or, 54 - 12 x - 4 x = 22

Or, 12 x + 4 x = 54 - 22

Or, 16 x = 32

∴ x = $\dfrac{32}{16}$

i.e x = 2

Now, Put the value of x into eq 2

∴ y = 9 - 2 x

So, y = 9 - 2 × 2

Or, y = 9 - 4

i.e y = 5

So, The value of x , y = 2 , 5

Hence, The value of x , y using substitution method is 2 , 5 Answer

7 0

3 years ago

Read 2 more answers

8) 6x2 - 4x - 15 = 0 a = b= c= _+(+72-400 20)

IgorC [24]

Answer:

63‾√2

Step-by-step explanation:

3 0

4 years ago

Melanie plays softball and is hitting 30% of the balls pitched to her. If she has hit the ball 39 times, about how many times ha

arsen [322]

P(30/100)=39 multiply both sides by 100

30p=3900 divide both sides by 30

p=130

So she has faced 130 pitches.

7 0

3 years ago

Read 2 more answers

Simplify 6/2√3-√6+√6/√3+√2- 4√3/√6-√2

kkurt [141]

Answer:

-sqrt(2) + 3 sqrt(3) - sqrt(6)

Step-by-step explanation:

Simplify the following:

(6 sqrt(3))/2 - sqrt(6) + (sqrt(6))/(sqrt(3)) + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

6/2 = (2×3)/2 = 3:

3 sqrt(3) - sqrt(6) + (sqrt(6))/(sqrt(3)) + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

Rationalize the denominator. (sqrt(6))/(sqrt(3)) = (sqrt(6))/(sqrt(3))×(sqrt(3))/(sqrt(3)) = (sqrt(6) sqrt(3))/3:

3 sqrt(3) - sqrt(6) + (sqrt(6) sqrt(3))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

sqrt(6) sqrt(3) = sqrt(6×3):

3 sqrt(3) - sqrt(6) + (sqrt(6×3))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

6×3 = 18:

3 sqrt(3) - sqrt(6) + (sqrt(18))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

sqrt(18) = sqrt(2×3^2) = 3 sqrt(2):

3 sqrt(3) - sqrt(6) + (3 sqrt(2))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

(3 sqrt(2))/3 = 3/3×sqrt(2) = sqrt(2):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

Rationalize the denominator. (-4 sqrt(3))/(sqrt(6)) = (-4 sqrt(3))/(sqrt(6))×(sqrt(6))/(sqrt(6)) = (-4 sqrt(3) sqrt(6))/6:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) + (-4 sqrt(3) sqrt(6))/6 - sqrt(2)

The gcd of -4 and 6 is 2, so (-4 sqrt(3) sqrt(6))/6 = ((2 (-2)) sqrt(3) sqrt(6))/(2×3) = 2/2×(-2 sqrt(3) sqrt(6))/3 = (-2 sqrt(3) sqrt(6))/3:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) + (-2 sqrt(3) sqrt(6))/3 - sqrt(2)

sqrt(3) sqrt(6) = sqrt(3×6):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2/3 sqrt(3×6) - sqrt(2)

3×6 = 18:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - (2 sqrt(18))/3 - sqrt(2)

sqrt(18) = sqrt(2×3^2) = 3 sqrt(2):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2/3 3 sqrt(2) - sqrt(2)

Combine powers. (-2×3 sqrt(2))/3 = 2 sqrt(2)×3^(1 - 1) (-1):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2)×3^(1 - 1) - sqrt(2)

1 - 1 = 0:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2)×3^0 - sqrt(2)

3^0 = 1:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2)×1 - sqrt(2)

Add like terms. 3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2) - sqrt(2) = -sqrt(2) + 3 sqrt(3) - sqrt(6):

Answer: -sqrt(2) + 3 sqrt(3) - sqrt(6)

7 0

4 years ago

Can any one help me on 8&9

vodomira [7]

8 is x-intercept and 9 is y-intercept

5 0

4 years ago