15
300*5/100 =15
That's all
Answer:
Minimum percent of the vote that candidate Towne is expected to recieve:
m=51% - 6.3% * 51% =47.787%
Maximum percent of the vote that candidate Towne is expected to recieve:
M=51% + 6.3% * 51% = 54.213%
Solution:
Margin of error: E=6.3%
Minimum percent of the vote that candidate Towne is expected to recieve:
m=51% - E * 51%
m=51% - 6.3% * 51%
m=51% - 51% * 6.3 / 100
m=51% - 3.213%
m=47.787%
Maximum percent of the vote that candidate Towne is expected to recieve:
M=51% + E * 51%
M=51% + 6.3% * 51%
M=51% + 51% * 6.3 / 100
M=51% + 3.213%
M=54.213%
Answer:
Step-by-step explanation:
Since, The total number of student = 300
Out of which,
The number of students who are only in Maths = 120
And, The number of students who are only in Science = 50
While, the students who are not from any subject = 100
Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None
= 300 - 120 - 50 - 100
= 30
That is, there are 30 students who are both from science and maths,
Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10