The intersecting secant-tangent theorem says that

where T is the point at which line segment PO touches the circle. Similarly,

so we have

OP is of course as long as itself, and AO and BO are radii of the same circle so they have the same lengths.
This means triangles APO and BPO are congruent, which means angles APO and BPO are congruent, so angle APB is bisected by PO.
Answer:
My answer would be y=2x+1
Step-by-step explanation:
Type in the question without g(x)
Answer:
Option (3)
Step-by-step explanation:
By applying cosine rule in the triangle ABC,
BC² = AC² + AB² - 2(AC)(AB)cosA
5² = 3² + 7²- 2(3)(7)cosA
25 = 9 + 49 - 42cos(A)
25 = 58 - 42cos(A)
cos(A) = 
A = 
A = 38.21°
A ≈ 38°
Option (3) will be the correct option.