Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56
fts
Now using Formula for time and range as
Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,
T is approximately equals to 4 sec.
Answer:8.5 is x but there is an extra 1
Step-by-step explanation:18x8.5=153+8=162 with an extra one is 162
Answer:
A box-and-whisker plot is shown above a number line that extends from 70 to 100 with 1 unit markings. The box extends from 79 to between 90 and 91 with a division at 89. There is also a point marked at 89. The whisker on the left extends from 75 to 79. The whisker on the right extends from between 90 and 91 to 93.
i hope this helps u and makes sense :))
In slope intercept form this would be equal to y=-7x-8. (remember the 7 is negative!)
I like to use Desmos Graphing Calculator. The attachment is what I get when I plug the inequalities in.
