A method to solve such problems is to consider the rate of change of the angle in degrees per minute. The hour hand of a normal 12-hour analogue clock turns 360° in 12 hours (720 minutes) or 0.5° per minute. The minute hand rotates through 360° in 60 minutes or 6° per minute.
A.) P(t) = P0exp(kt)
P(20/60) = 40 exp(20k/60)
80 = 40 exp(k/3)
exp(k/3) = 80/40 = 2
k/3 = ln(2)
k = 3ln(2)
b.) P(8) = 40(2)^24 = 40(16777216) = 671088640 cells
d.) Rate of change = exp(8k) = exp(8(3ln(2)) = exp(24ln(2)) = exp(16.6355) = 16777216 cells / hour
e.) P(t) = 40(2)^3t; t in hours
1,000,000 = 40(8)^t
25,000 = 8^t
ln(25,000) = t ln(8)
t = ln(25,000)/ln(8) = 4.87 hours
40 degrees is your answer. Just click your pic and use a protracter and get 40. I hope I helped!
System of equations to be solved simultaneously
In any function y = f(x) , set of all possible values of x define the domain of f(x), in the graph The curve in terms of x-axis(in 1st & 3rd quadrant) goes from -4 to -2(doesnt include -2).
So domain = [-4, -2)
Similarly, in 2nd and 4th quadrant, for x-axis
It goes from 2 to 5 (doesnt include 2 & 5)
So domain = (2, 5)
Hence,
Domain of the f(x) is [-4, -2) U (2, 5).
Range tells the possible values of y, for this function it goes from -5 to +3(doesnt include 3).
Range is [-5, 3)
