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FinnZ [79.3K]
4 years ago
9

How do you solve this?

Mathematics
1 answer:
Ronch [10]4 years ago
7 0

Answer:

The highest possible value of b would be 750.

Step-by-step explanation:

If you graph the two equations, you'll get two crossing lines, and because y is supposed to be either equal to or less, the answer is going to be at the shaded area at the bottom.

Equate the two equations to solve them with algebra.

-15x+3000=5x

add 15x to both sides

3000=20x

divide by twenty, you get

150=x

Plug that in to both equations, you'll get y=750, which is the highest possible value of b, (aka y cuz it's on the y axis).

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The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

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Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

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4 years ago
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