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user100 [1]
3 years ago
13

What is the answeeerrrr? i need helpppp now for a test .

Mathematics
2 answers:
Fynjy0 [20]3 years ago
7 0
Second answer choice

almond37 [142]3 years ago
4 0

Answer:

b\sqrt{a}

Step-by-step explanation:

\sqrt{ab^{2} }=b\sqrt{a}

Sorry I didn't explain better, but in a rush. hope this helps though!

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6-1/3x=-1 How do I do this
I am Lyosha [343]
Im gonna assume you mean 6 - (1/3)x = -1.  Your notation is not super clear.  If so, solution is as follows:

6 - (1/3)x = -1   [subtract 6 from both sides]
-(1/3)x = -7       [multiply both sides by -3]
x = 21

7 0
4 years ago
The following equation represents the number of fish in a pond, F(x), after x number of weeks. F(x) = 500 (1.2)x. How many fish
Shalnov [3]

Answer:

1) d. 2400

2) d.4200

Step-by-step explanation:

As per given data:

F(x) represents number of fish

x represents number of weeks

Relation between F(x) and x is given as

F(x)= 500 (1.2)x

Now part 1:

How many fish are in the pond after 4 weeks=?

x=4

Putting in given equation  F(x)= 500 (1.2)x

F(x)= 500(1.2)(4)

     = 2400

Now part 2:

How many fish are in the pond after 7 weeks?

x=7

Putting in given equation  F(x)= 500 (1.2)x

F(x)= 500(1.2)(7)

     = 4200 !

7 0
3 years ago
Read 2 more answers
Solve pls brainliest
Ulleksa [173]

Answer:

only 16

Step-by-step explanation:

18/2=9 not 8

12/2=6 not 8

16/2=8

20/2= 10 not 8

5 0
2 years ago
Read 2 more answers
A survey showed that 82​% of adults need correction​ (eyeglasses, contacts,​ surgery, etc.) for their eyesight. If 12 adults are
Aloiza [94]

Probability of an adult who needs correction = 82% or 0.82

So, probability of an adult who does not needs correction = 1 - 0.82  = 0.18

If 12 adults are randomly​ selected, the probability that at least 11 of them need correction for their eyesight is:

12C11(0.82)^{11}(0.18)^{12-11} + 12C12(0.82)^{12}(0.18)^{12-12}

= 12*0.11*0.18 + 1*0.09*1

= 0.238+0.09

= 0.328 or 0.33

And, yes, 11 is significantly a high number of adults requiring eyesight​ correction.

7 0
3 years ago
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YO PLEASE HELP MY TEST IS ALMOST DUE!!!!!!!!
Inga [223]

Answer:

3: x=-1

4: x=4

5: 0=0 infinite solutions

6: x=-3

3 0
3 years ago
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