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Lady_Fox [76]
3 years ago
10

Regular quadrilateral pyramid with base edge b=55 mm and lateral edge l=7 cm. Find the sum of all edges

Mathematics
2 answers:
Lelu [443]3 years ago
4 0
The correct answer is 50 cm or 500 mm. There are 4 base edges and 4 lateral edges, so just multiply the number for both edges by 4 and add. The question threw a curveball at us by giving us two units of measurement, millimeters and centimeters, but since we know that there are 10 millimeters in a centimeter, we can just divide 55 by 10 to get 5.5.

5.5 x 4 = 22
7 x 4 = 28
28 + 22 = 50

If it helps, you can draw the figure and label the edges. Remember that the lateral edge of a quadrilateral pyramid is the slanted line leading up to the top of the pyramid, and that the base edges are the sides of the quadrilateral on the bottom.

Hope this helps!
AlladinOne [14]3 years ago
3 0

Answer:

50

Step-by-step explanation:

55 · 4 - 10 · 7 = 220 - 70

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What is the recursive rule for an=4n−1? a1=4;an=an−1−1 a1=3;an=an−1+4 a1=−1;an=an−1+4 a1=3;an=an−1−1
navik [9.2K]
Plug in n = 1 into the nth term formula
a(n) = 4n-1
a(1) = 4*1-1
a(1) = 3
So the first term is 3

The second term will be 7 because we add on 4 each time, as indicated by the slope of 4. This is also known as the common difference.

So the nth term is found by adding 4 to the (n-1)st term, in other words,
a(n) = a(n-1)+4

----------------------------------------------------------------------------

In summary, the answer is 
a1=3; an=an-1+4
which is choice B
4 0
2 years ago
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mamaluj [8]
32×10×10×10×10×10×10
5 0
3 years ago
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Choose the product. a 3 b 2 · 4ab 3 <br><br> 4a3b5<br><br> 4a3b6<br><br> 4a4b5
zvonat [6]
A³ b² 4ab³

Rearrange order:

4  a³ a  b² b³

Now add up the exponents from same base:

4  a³⁺¹  b²⁺³

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5 0
3 years ago
Problem PageQuestion It takes an older pump twice as long to drain a certain pool as it does a newer pump. Working together, it
umka2103 [35]

Answer:

It will take 6 hours for the new pump to drain the pool.

Step-by-step explanation:

As the complete question is not given, the complete question is found online and is attached herewith

Let the rate of new pump is given as x=W/t_1

Let the rate of the old pump is given as y=W/t_2

it is given that the time t_2=2t_1

So by substituting the values of t_2 in the rate equation of y

y=W/2t_1

y=(W/t_1*2)=x/2

Also the total rate of both the pumps is given as W/t3 where t3 is given as 4 hours so the equation becomes

x+y=W/4

x+x/2=W/4

3x/2=W/4

As x=W/t_1

3W/2t_1=W/4

Now as W is same on both sides so

3/2t_1=1/4

12=2t_1

t_1=6 hours

So it will take 6 hours for the new pump to drain the pool.

7 0
3 years ago
HELP ASAP- I would give 40 points just for these 3 answers
Slav-nsk [51]
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Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.


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8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
7 0
3 years ago
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