Answer:
Area=190.091 cm^2
Step-by-step explanation:
Area = 1/2(Pi x r^2) one-half because it's a semi-circle
Area=1/2(3.14 x 11^2)
11^2=121 so, Area=1/2(3.14 x 121)
Area=1/2(379.94)
Area=189.97 cm^2
adjustment:
Area=1/2(3.142 x 11^2)
Area=1/2(3.142 x 121)
Area=1/2(380.182)
Area=190.091
Answer: b. 134
Step-by-step explanation:
Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.
Let x denotes a usual value.
i.e. 135.8< x < 155.9
Therefore , the interval for the usual values is [135.8, 155.9] .
If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.
Let's check all options
a. 137 ,
since 135.8< 137 < 155.9
So , it is usual.
b. 134
since 134<135.8 (Minimum value)
So , it is unusual.
c. 146
since 135.8< 146 < 155.9
So , it is usual.
d. 155
since 135.8< 1155 < 155.9
So , it is usual.
Hence, the correct answer is b. 134 .
Answer:
20
Step-by-step explanation:
Answer:
Step-by-step explanation:
PLEASE MARK BRAINLIEST
In the x quarts of 2% fat milk, there is 0.02x quarts of fat.
in the y quarts of 4% fat milk there is 0.04y quarts of fat.
together, there is (x+y) quarts of milk, and 0.24 quarts of fat.
the equations are:
x+y=9
0.02x+0.04y=0.24
multiply the first equation with 0.02: 0.02x+0.02y=0.18
subtract this new equation from equaition 2 to eliminate x:
0.04y-0.02y=0.24-0.18
0.02y=0.06
y=3
x=9-3=6
x is twice as much as y.
He used twice as much as the 2% fat milk than the 4% fat milk.
so the first choice is the correct answer.
