The point-slope form of a line is:
y-y1=m(x-x1), where m=slope and (x1,y1) is any point on the line
First we need to find the slope, which is (y2-y1)/(x2-x1)
m=(4--1)/(8-2)
m=5/6 and we can use either point, I'll use (8,4)
y-4=(5/6)(x-8)
That is your equation in point-slope form.
Now the standard equation of a line is ax+by=c
y-4=(5/6)(x-8) we can perform the indicated multiplication on the right side
y-4=(5x-40)/6 multiply both sides by 6
6y-24=5x-40 add 24 to both sides
6y=5x-16 subtract 5x from both sides
-5x+6y=-16 and by convention, the standard equation of a line should be expressed with a positive coefficient for x, so multiply both sides by -1
5x-6y=16
Answer:
2p+3>2(p−3)
Use the distributive property to multiply 2 by p−3.
2p+3>2p−6
Subtract 2p from both sides.
2p+3−2p>−6
Combine 2p and −2p to get 0.
-3>6
This is true for any p.
p∈R
Step-by-step explanation:
Hope this helps! :)
Answer:
plot points
y=-2x+1
(0,1)
(1,-1)
plot points
y=-5x+4
(0,4)
(1,-1)
Step-by-step explanation:
6 because if you add the negative 8 (it would become a positive 8) to the other side (to negative 2) then it equals 6 I hope that makes sense
