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jeka57 [31]
3 years ago
6

PLEASE HELP!!!! DUE TODAY!!!

Mathematics
1 answer:
Nastasia [14]3 years ago
6 0
<h3>Answer: Choice C. </h3><h3>Division[ (4x^3+2x^2+3x+5)^2, x^2+3x+1]</h3>

=============================================================

Explanation:

It honestly depends on the CAS program, but for GeoGebra for instance, the general format would be Division[P, Q]

Where,

  • P = numerator = (4x^3+2x^2+3x+5)^2
  • Q = denominator = x^2+3x+1

As another example, let's say we want to divide x^2+5x+6 all over x^3+7 as one big fraction

We would type in Division[x^2+5x+6, x^3+7]

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Given the functions f(x) = − 4x − 1 and g(x) = 2x + 4, which operation results in the smallest coefficient on the x term?
Sedbober [7]
F(x)=-4x-1 if you sub 3 into it you get 3(-4)-1 which is -13 and 2x+4=10
4 0
3 years ago
Read 2 more answers
0.8) 498 what is the answer​
Lina20 [59]

Step 1: We make the assumption that 498 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$x​.

Step 3: From step 1, it follows that $100\%=498$100%=498​.

Step 4: In the same vein, $x\%=4$x%=4​.

Step 5: This gives us a pair of simple equations:

$100\%=498(1)$100%=498(1)​.

$x\%=4(2)$x%=4(2)​.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{498}{4}$

100%

x%​=

498

4​​

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{4}{498}$

x%

100%​=

4

498​​

$\Rightarrow x=0.8\%$⇒x=0.8%​

Therefore, $4$4​ is $0.8\%$0.8%​ of $498$498​.

7 0
3 years ago
On a particular production line,the likelihood that a light bulb is defective is 5%. Ten light bulbs are randomly selected. What
KengaRu [80]

Answer:

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

Step-by-step explanation:

Consider the provided information,

Let X is the number of defective bulbs.

Ten light bulbs are randomly selected.

The likelihood that a light bulb is defective is 5%.

Therefore sample size is = n = 10

Probability of a defective bulb = p = 0.05.

Therefore, q = 1 - p = 1 - 0.05 = 0.95

Mean of binomial random variable: \mu=np

Therefore, \mu=10(0.05)=0.5

Variance of binomial random variable: \sigma^2=npq

Therefore, \sigma^2=10(0.05)(0.95)=0.475

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

5 0
3 years ago
Please see attachment for the question.
Sophie [7]

Step-by-step explanation:

\frac{10 {x}^{3}  -  12 {x}^{2}   + 6x - 7 }{ - 14 {x}^{2} - 1 }

-14x²-1≠0

x²≠ -1/14

Option C

5 0
4 years ago
Can someone help me calculate angles? P3
just olya [345]

Answer:

the little box would indicate that it is a 90 degree angle.

4 0
3 years ago
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