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Studentka2010 [4]
3 years ago
8

Find the area of the right triangle with a base of 38cm and the height of 26cm

Mathematics
1 answer:
sesenic [268]3 years ago
8 0
The answer is D!

Area for a triangle solution is 1/2(b•h)
Insert each number!
1/2(38•26)
Area = 494cm
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Find the product. (y^3)^2 * y^7
Natasha_Volkova [10]
Firstly, let's take first factor:
(y^3)^2 = y^(3*2) = y^6
and then:
y^6 * y^7 = y^(6 + 7) = y^13

8 0
3 years ago
The radius of a circle is 1 centimeter. What is the circle's circumference?
igomit [66]

Answer:

6.28 cm

Step-by-step explanation:

The formula for the circumference of a circle with radius r is C = 2*pi*r.

If we let pi = 3.14 and r = 1 cm, then the circumference of this circle is

C = 2(3.14)(1 cm) = 6.28 cm

6 0
3 years ago
1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o
tester [92]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<u><em>A) If the length of a rectangle was tripled, but the  width did not change?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<u><em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

5 0
3 years ago
PLEASE HELP! WILL MARK BRAINLIEST!!
Alecsey [184]

Answer:

The y-intercept is (0,1).  The x values at the horiz. intercepts are:

{ (-3+√5)/2, (-3-√5)/2 }.  Graph is that of a parabola that opens down.

Step-by-step explanation:

It'd be helpful to rewrite f(x) = 3-x2+3x-2 with the powers of x in descending order and using " ^ " to denote exponentiation:

f(x) = -x^2 + 3x -2 + 3, or

f(x) = -x^2 + 3x + 1

y-intercept:  let x = 0.  Then f(0) = 1.  The y-intercept is (0,1)

x-intercepts:  let y = f(x) = 0 = -x^2 + 3x + 1.  Let's use the quadratic formula with a = -1, b = 3 and c = 1 to determine the roots of this polynomial.  The discriminant, b^2-4ac, is 9-4(1)(1), or 5.

Thus, there are two real, unequal roots.  They are:

       -3 plus or minus √5

x =  ---------------------------------

                     2


or { (-3+√5)/2, (-3-√5)/2 }

These are your two horizontal intercepts, where the function is zero.

Because the coefficient -1 of the x^2 term is negative, the parabola representing this function opens down.

8 0
3 years ago
What causes the normal ocean waves that continuously crash on the beach? A. Wind B. Upwelling C. The moon D. Earthquakes
stira [4]
The answer is A: Wind
8 0
3 years ago
Read 2 more answers
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