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AlladinOne [14]
3 years ago
7

PLEASE HELP FIRST CORRECT ANSWER GETS BRAINLIEST!!!!!!!!!

Mathematics
1 answer:
andreev551 [17]3 years ago
7 0
1st calculate the hypotenuse of the right triangle with one side =|-7| and the second side = |-14|
(Hypotenuse)² = 7² + 14² = 625 & Hypotenuse = √625 = 25; now that we have the hypotenuse we can calculate all 6 trigo values:

a) sin Ф = (opposite side) / (hypotenuse) = -14/25  (the student gave a wrong answer).

b) cos Ф = (adjacent) /(hypotenuse) = -7/25 (Right answer)

c) tan Ф = (opposite side) / (adjacent) = -14/ -7 = 14/7 = 2 (the student gave a wrong answer)

d) csc Ф = 1/sin Ф = (1) : (-14/25) = - 25/14 (the student gave a wrong answer)

e) sec Ф = 1/cos Ф = -25/7 ( Right question)

f) cot Ф = 1/tan Ф = 1/2 (the student gave a wrong answer)
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If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No
Effectus [21]

If A and B are independent, then P(A\cap B)=P(A)P(B).

a.

P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)

P(A\cup B)=0.5+0.2-0.5\cdot0.2

\boxed{P(A\cup B)=0.6}

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)

P(A^c\cap B^c)=1-0.6

\boxed{P(A^c\cap B^c)=0.4}

c. DeMorgan's law can be used here too:

P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)

P(A^c\cup B^c)=1-0.5\cdot0.2

\boxed{P(A^c\cup B^c)=0.9}

4 0
3 years ago
Can anyone pls help me with this I'll mark as brainlist for correct answer please do explain in detail each answers Ty! (I'm pre
densk [106]

<u>Question 8</u>

a^2 + 7a + 12

= (a+3)(a+4)

When factorising a quadratic, the product of the two factors should equal the constant term (12), and the sum of the two factors should equal the linear term (7). To find the two factors, list out the factors of 12 (1x12, 2x6, 3x4) and identify the pair that adds up to 7 (3+4).

An alternative method if you get stuck during your exam would be to solve it algebraically using the quadratic formula and then write it in the factorised form.

a = (-7 +or- sqrt(7^2 - 4(1)(12)) / 2(1)

= (-7 +or- sqrt(1))/2

= -3 or -4

These factors are the negative of the values that would go in the brackets when written in factorised form, as when a = -3 the factor (a+3) would equal 0. (If it were positive 3 instead, then in the factorised form it would be a-3).

<u>Question 10</u>

-3(x - y)/9 + (4x - 7y)/2 - (x + y)/18

Rewrite each fraction with a common denominator so you can combine the fractions into one.

= -6(x - y)/18 + 9(4x - 7y)/18 - (x + y)/18

= (-6(x - y) + 9(4x - 7y) - (x + y)) /18

Expand the brackets and collect like terms.

= (-6x + 6y + 36x - 63y - x - y)/18

= (29x - 58y)/18

= 29/18 x - 29/9 y

7 0
2 years ago
A tin is a right circular cylinder with a diameter of 6 meters and a height of 10 meters. What is the surface area of this tin,
Alex777 [14]

Answer:

245.04

Step-by-step explanation:

A=2πrh+2πr2=2·π·3·10+2·π·32≈245.04423

Divide 6 by 2 to find the radius

5 0
3 years ago
The sum of three consecutive numbers (numbers in order one after another is 84. What are the three numbers? ________+ ________ +
Serggg [28]

Answer:

The answer is 27, 28, 29.

3 0
2 years ago
Mrs.Smith buys 4 packs of stickers with 12 stickers in each pack. She already has 8 stickers. Which equation shows how to calcul
Ugo [173]

Answer: Should be 56 Stickers


Step-by-step explanation:

4*12 =48 + 8 = 56 but since I dont have the pictures dont really have proof that im right

6 0
3 years ago
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