1st calculate the hypotenuse of the right triangle with one side =|-7| and the second side = |-14| (Hypotenuse)² = 7² + 14² = 625 & Hypotenuse = √625 = 25; now that we have the hypotenuse we can calculate all 6 trigo values:
a) sin Ф = (opposite side) / (hypotenuse) = -14/25 (the student gave a wrong answer).
b) cos Ф = (adjacent) /(hypotenuse) = -7/25 (Right answer)
c) tan Ф = (opposite side) / (adjacent) = -14/ -7 = 14/7 = 2 (the student gave a wrong answer)
d) csc Ф = 1/sin Ф = (1) : (-14/25) = - 25/14 (the student gave a wrong answer)
e) sec Ф = 1/cos Ф = -25/7 ( Right question)
f) cot Ф = 1/tan Ф = 1/2 (the student gave a wrong answer)
