Answer:
5.8 g of carbon dioxide are produced
Explanation:
The Law of Conservation of Mass states that the mass of the reactants must equal the mass of the products in all chemical reactions.
This is the chemical reaction (combustion)
CH₄ + 2O₂ → CO₂ + 2H₂O
12.2 g 14 g x 20g
Mass in reactants = 12.2 g + 14 g = 26.2 g
Mass in products = x + 20 g
26.2 g = x + 20g
26.2 g - 20g = x
5.8 g = x
The plant will grow less than 5 centimeters because it is a seedless, non-vascular plant. The correct option is B.
<h3>What are moss plants?</h3>
Moss plants are those plants that do contain seeds or flowering plants. They are non-vascular plants, and they maintain the moisture of the soils. They are very small plants.
Moss plants are small plants that grow in moist and humid conditions. They do not need so much sunlight. They will grow less than 5 centimeters and wet conditions.
Thus, the correct option is B. less than 5 centimeters because it is a non-vascular plant.
To learn more about moss plants, refer to the link:
brainly.com/question/3329215
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Answer is: mass in grams of KOH is 1,68.
m(KBr + KOH) = 5,50 g.
m(K) = 2,45 g.
M(KBr) = 39 g/mol + 80 g/mol = 119 g/mol.
M(KOH) = 39 g/mol + 16 g/mol + 1 g/mol = 56 g/mol.
ω(K) = 2,45 g ÷ 5,50 g.
ω(K) = 0,445 = 44,5%.
n(K) = m(K) ÷ M(K).
n(K) = 2,45 g ÷ 39 g/mol.
n(K) = 0,062 mol.
m(Br + OH) = 5,50 g - 2,45 g = 3,05 g.
n(K) = n(KBr + KOH) = 0,062 mol.
M(KBr + KOH) = 5,50 g ÷ 0,062 mol = 88,7 g/mol.
Set two equations:
1) m(KBr) + m(KOH) = 5,50 g.
2) m(KBr)/M(KBr) + m(KOH)/M(KOH) = 0,062 mol.
m(KOH) = 5,50 g - M(KBr), put that in second equation.
m(KBr) = 3,82 g.
m(KOH) = 5,50 g - 3,82 g = 1,68 g.
Answer:
1.2kg or 1200kg
Explanation:
F = ma
net force = 1,800
m = ??
a = 1.5m/s^2
m = F/a = 1,800/1.5 or 1,800 x 10/1.5 x 10
= 18,000/15 = 1,200kg or 1.2kg
Thanks
