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masha68 [24]
3 years ago
12

______has gate cells​

Mathematics
1 answer:
yaroslaw [1]3 years ago
3 0

Answer:

gating

Step-by-step explanation:

This is your answer

You might be interested in
which expression is equivalent to the expression shown? 3 to the power of 7 X 3 to the power os negative 4
grandymaker [24]

Answer:

The answer is 27

Step-by-step explanation:

I worked it out using a calculator

5 0
3 years ago
The water level in a pool is currently at 1/2 of an inch. Every hour, the water level increases 4.75 inches. How many hours will
____ [38]

Answer:

7.1 hours

Step-by-step explanation:

Given data

Let the number of hours taken to fill the pool be x

the current quantity is 1/2 the capacity of the pool

we are given that the rate of flow = 4.75 in per hour

let the total amount of water after x hours be y, the expression for the quantity of water is given as

y= 0.5+4.75x

if y= 33.75 in, let us find x

33.75= 0.5+4.75x\\\\33.75-0.5= 4.75x\\\\33.25= 4.75x\\\\

divide both sides by 4.75

x= 33.75/4.75\\\\x= 7.10

Hence, it will take 7.1 hours

6 0
3 years ago
Which expression is equivalent to 3m + 1 - m?<br><br> 2 + m - 1 + - m<br> 1 + m<br> 3m - 1<br> 3m
Rasek [7]

Answer:

I  believe it would be A) 2 + m - 1 + - m

5 0
3 years ago
Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting
slega [8]

Answer:

(a) <em>λ</em> = 2.

(b) P (X = 0) = 0.1353; P (X = 1) = 0.2706;

    P (X = 2) = 0.2706; P (X = 3) = 0.1804

(c) P (Delay Problems) = 0.1431.

Step-by-step explanation:

Let <em>X</em> = number of arrivals at the drive-up teller window.

The average number of arrivals at the drive-up teller window per minute is,

<em>p</em> = 0.4 customers/ minute.

(1)

Compute the expected number of customers at the drive-up teller window in <em>n</em> = 5 minutes as follows:

E(X)=\lambda\\=np\\=5\times 0.4\\=2

Thus, the mean number of customers that will arrive in a five-minute period is <em>λ</em> = 2.

(2)

The random variable <em>X</em> follows a Poisson distribution with parameter λ = 2.

The probability mass function of <em>X</em> is:

P(X=x)=\frac{e^{-2}2^{x}}{x!};\ x=0,1,2,3...

Compute the probability of exactly 0 arrivals in 5 minutes as follows:

P(X=0)=\frac{e^{-2}2^{0}}{0!}=\frac{0.1353\times 1}{1}=0.1353

Compute the probability of exactly 1 arrivals in 5 minutes as follows:

P(X=1)=\frac{e^{-2}2^{1}}{1!}=\frac{0.1353\times 2}{1}=0.2706

Compute the probability of exactly 2 arrivals in 5 minutes as follows:

P(X=2)=\frac{e^{-2}2^{2}}{2!}=\frac{0.1353\times 4}{2}=0.2706

Compute the probability of exactly 3 arrivals in 5 minutes as follows:

P(X=3)=\frac{e^{-2}2^{3}}{3!}=\frac{0.1353\times 8}{6}=0.1804

Thus, the values are:

P (X = 0) = 0.1353

P (X = 1) = 0.2706

P (X = 2) = 0.2706

P (X = 3) = 0.1804

(3)

Delays occur in the service time if there are more than three customers arrive during any five-minute period.

Compute the probability that there are more than 3 customers as follows:

P (X > 3) = 1 - P (X ≤ 3)

              =1-\sum\limits^{3}_{x=0}{\frac{e^{-2}2^{x}}{x!}}\\=1-(0.1353+0.2706+0.2706+0.1804)\\=1-0.8569\\=0.1431

Thus, the probability that delays will occur is 0.1431.

3 0
4 years ago
A plane flew 3,100 kilometers at a speed of 775 kilometers per hour how many hours was the flight?
Tom [10]
3100 divided by 775 equal 4 hours
4 0
3 years ago
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