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bazaltina [42]
1 year ago
10

On December 13, 2007, one British pound was worth 2.04 U.S. dollars.

Mathematics
1 answer:
Alika [10]1 year ago
3 0

Answer:

a) 5 pounds

b) 365 dollars

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Since the 4 is a smaller digit than a 5, the 6 in the tens place would stay the same while the 4 would become a 0.
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Jill is shopping at a department store that is having a sale this week. The store has advertised 15% off certain merchandise. Ji
Phantasy [73]

Answer:

The simpler way is:

SP = 0.85*RP

Step-by-step explanation:

Suppose that we have a given amount A. and now we take a given percentage, X%, off.

The new amount will be:

New amount = A - (X%/100%)*A = A*(1 - X%/100%)

This is the general formula.

In this case, we know that the store has advertised 15% off, then we have X% = 15%

Then if:

SP = sales price

RP = regular price

We will have the equation:

SP = RP - (15%/100%)*RP = RP - 0.15*RP

This is what Jill found, but if we use the general equation above, we will find that:

SP = RP*(1 - 15%/100%) = RP*(1 - 0.15) = RP*0.85

So we just need to multiply the regular price by 0.85 to get the sales price.

6 0
2 years ago
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2x + y = 3<br> 4x + 4y = 8
den301095 [7]

Answer:

Point form : (1,1)

Equation form : x=1 , y=1

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Hope this helps you out! ☺

7 0
3 years ago
(b) For those values of k, verify that every member of the family of functions y = A sin(kt) + B cos(kt) is also a solution. y =
frutty [35]

Answer:

Check attachment for complete question

Step-by-step explanation:

Given that,

y=Coskt

We are looking for value of k, that satisfies 4y''=-25y

Let find y' and y''

y=Coskt

y'=-kSinkt

y''=-k²Coskt

Then, applying this 4y'"=-25y

4(-k²Coskt)=-25Coskt

-4k²Coskt=-25Coskt

Divide through by Coskt and we assume Coskt is not equal to zero

-4k²=-25

k²=-25/-4

k²=25/4

Then, k=√(25/4)

k= ± 5/2

b. Let assume we want to use this

y=ASinkt+BCoskt

Since k= ± 5/2

y=A•Sin(±5/2t)+ B •Cos(±5/2t)

y'=±5/2ACos(±5/2t)-±5/2BSin(±5/2t)

y''=-25/4ASin(±5/2t)-25/4BCos(±5/2t

Then, inserting this to our equation given to check if it a solution to y=ASinkt+BCoskt

4y''=-25y

For 4y''

4(-25/4ASin(±5/2t)-25/4BCos(±5/2t))

-25A•Sin(±5/2t)-25B•Cos(±5/2t).

Then,

-25y

-25(A•Sin(±5/2t)+ B •Cos(±5/2t))

-25A•Sin(±5/2t) - 25B •Cos(±5/2t)

Then, we notice that, 4y'' is equal to -25y, then we can say that y=Coskt is a solution to y=ASinkt+BCoskt

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The sequence is 4, 5, 6, 7, 8, ..... The pattern is: Each term is (the term before it) plus (1).
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