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Sergeeva-Olga [200]
3 years ago
9

If a+b= -1 then the value of a^3+b^3 - 3ab= ?

Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

-1

Step-by-step explanation:

(a + b)^{3}  =  {a}^{3}  +  {b}^{3}  + 3ab(a + b) \\ ( - 1)^{3}  =  {a}^{3}  +  {b}^{3}  + 3ab( - 1) \\  - 1 =  {a}^{3}  +  {b}^{3}   -  3ab\\  \\  \huge \red{ \boxed{{a}^{3}  +  {b}^{3}   -  3ab =  - 1}}

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Option B and D .....

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2 years ago
Find the cos A and tan B to four decimal places. URGENT
Nikolay [14]

cos A is 0.8511 and tan B is 1.6

Step-by-step explanation:

Find the 3rd length or the hypotenuse.

<u>Pythagoras theorem</u>

hypotenuse^{2} = adjacent^{2} + opposite^{2}

hypotenuse^{2} = 8^{2} + 5^{2}

hypotenuse^{2} = 64 + 25

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<u>Data:</u>

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<u>Formula:</u>

Cos (Angle) = \frac{adjacent}{hypotenuse}

Cos A =  \frac{8}{9.4}

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b) Tan B

<u>Data: </u>

Opposite = 8

Adjacent = 5

<u>Formula:</u>

Tan (Angle) = \frac{opposite}{adjacent}

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B =  cos^{-1} (1.6)

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Therefore, cos A is 0.8511 and tan B is 1.6.

Keyword: cos, tan

Learn more about cos at

  • brainly.com/question/5013374
  • brainly.com/question/9532142

#LearnwithBrainly

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Answer:

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What are the missing angle measures for
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7 0
3 years ago
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