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Sergeeva-Olga [200]
3 years ago
9

If a+b= -1 then the value of a^3+b^3 - 3ab= ?

Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

-1

Step-by-step explanation:

(a + b)^{3}  =  {a}^{3}  +  {b}^{3}  + 3ab(a + b) \\ ( - 1)^{3}  =  {a}^{3}  +  {b}^{3}  + 3ab( - 1) \\  - 1 =  {a}^{3}  +  {b}^{3}   -  3ab\\  \\  \huge \red{ \boxed{{a}^{3}  +  {b}^{3}   -  3ab =  - 1}}

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Fiesta28 [93]

Answer:

18+81=9(x^{2}+6x+9)

11=(x+3)^{2}

Step-by-step explanation:

we have

0=9(x^{2} +6x)-18

Adds 18 both sides

18=9(x^{2} +6x)

Complete the square

18+81=9(x^{2}+6x+9)

99=9(x^{2}+6x+9)

Divide by 9 both sides

11=(x^{2}+6x+9)

Rewrite as perfect squares

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4 years ago
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lidiya [134]

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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TiliK225 [7]

Answer:

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