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3 years ago

If a+b= -1 then the value of a^3+b^3 - 3ab= ?

Mathematics

1 answer:

Neporo4naja [7]3 years ago

5 0

Answer:

-1

Step-by-step explanation:

$(a + b)^{3} = {a}^{3} + {b}^{3} + 3ab(a + b) \\ ( - 1)^{3} = {a}^{3} + {b}^{3} + 3ab( - 1) \\ - 1 = {a}^{3} + {b}^{3} - 3ab\\ \\ \huge \red{ \boxed{{a}^{3} + {b}^{3} - 3ab = - 1}}$

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Answer:

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3 years ago

Find the cos A and tan B to four decimal places. URGENT

Nikolay [14]

cos A is 0.8511 and tan B is 1.6

Step-by-step explanation:

Find the 3rd length or the hypotenuse.

Pythagoras theorem

$hypotenuse^{2}$ = $adjacent^{2}$ + $opposite^{2}$

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Formula:

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A = $cos^{-1}$ (0.8511)

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b) Tan B

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Opposite = 8

Adjacent = 5

Formula:

Tan (Angle) = $\frac{opposite}{adjacent}$

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B = $cos^{-1}$ (1.6)

B = 58°

Therefore, cos A is 0.8511 and tan B is 1.6.

Keyword: cos, tan

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3 years ago

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Answer:

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Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago