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Step2247 [10]
3 years ago
9

What is mQP? A.) 20° B.) 70° C.) 100° D.) 40° E.) 80°

Mathematics
1 answer:
Reil [10]3 years ago
4 0

Answer:

i think it might be b 70° sorry if it's not

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A. A newborn red panda weighs 100 grams. A
77julia77 [94]

Answer:

y=100\cdot (1.07)^d

Step-by-step explanation:

Find the expression to represent how much you would expect a cub to weigh d days after it's born as exponential growth function y=a\cdot b^d, where a is the initial panda's weight and b is the rate of growth.​

A newborn red panda weighs 100 grams, then a=100.

A healthy cub gains about 7% of its newborn weight per day, then

b=1+0.07=1.07

Hence,

y=100\cdot (1.07)^d

8 0
3 years ago
A computed measure of how much scores vary around the mean score
Paladinen [302]
That's called <span>standard deviation.

Hope this helps !

Photon</span>
5 0
3 years ago
I need help on this, if anyone knows how to do this can you help me out pls
ASHA 777 [7]
<h3>Answer:  (3, 0)</h3>

=================================================

Explanation:

Let's isolate x in the first equation.

x-2y = 3

x = 3+2y

Then we'll plug this into the second equation

Afterwards, solve for y.

2x + 4y = 6

2(3+2y)+4y = 6

6+4y+4y = 6

8y+6 = 6

8y = 6-6

8y = 0

y = 0/8

y = 0

Use this to find x.

x = 3+2y

x = 3+2(0)

x = 3

The solution is therefore (x,y) = (3, 0)

If you were to graph both lines, then they would intersect at the location (3,0).

-----------------------------

Checking the answer:

Plug x = 3 and y = 0 into the first equation.

x-2y = 3

3-2(0) = 3

3 - 0 = 3

3 = 3 that works

Repeat for the other equation

2x+4y = 6

2(3) + 4(0) = 6

6 + 0 = 6

6 = 6 that works as well

Both equations are true when (x,y) = (3,0).

The solution is confirmed.

6 0
3 years ago
Please help me. I need help please.
Mice21 [21]

Answer:

The correct options are;

EFGH has 4 congruent sides

Diagonal FH bisects angles EFG and EHG

Angle FEH is congruent to angle FGH

Step-by-step explanation:

1) Given that for a reflection, we have;

The distance of the reflected preimage from the line of reflection = The distance of the reflected image from the line of reflection

Therefore;

The distance of the point E from the line HF = The distance of the point G from the line HF

Also the reflection of an preimage (x, y) about the x-axis, gives an image (x, -y)

We can show that from the length of a line given by the equationl = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}, that the length EH ≅ GH and EF ≅ GF

Therefore since we are given that EH = EF, we have;

EH = GH = GF = EF by the definition of congruency, which gives 4 congruent sides

2) Given that EH = GH = GF = EF and HF = FH by reflective property, we have;

ΔEHF ≅ ΔGHF

∴ ∠GHF ≅ ∠EHF by Congruent Parts of Congruent Triangles are Congruent

Similarly, ∠GFH ≅ ∠EFH

Therefore, ∠GFH = ∠EFH and ∠GHF = ∠EHF

Therefore, diagonal FH bisects angles EFG and EHG

3) Given that ΔEHF ≅ ΔGHF, we have;

Angle FEH is congruent to angle FGH, by Congruent Parts of Congruent Triangles are Congruent

7 0
3 years ago
A polygon with four sides
Misha Larkins [42]
A polygon with four sides is known as a quadrilateral.
Quadrilaterals have four sides and four angles as well.
There's many different types of quadrilaterals:
square
rectangle
rhombus
trapezoid
The trapezoid has to meet qualifications to be considered a quadrilateral, such as a pair of parellel lines.
7 0
3 years ago
Read 2 more answers
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