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Step2247 [10]
3 years ago
9

What is mQP? A.) 20° B.) 70° C.) 100° D.) 40° E.) 80°

Mathematics
1 answer:
Reil [10]3 years ago
4 0

Answer:

i think it might be b 70° sorry if it's not

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A³b² a²b simplify the following expression
liberstina [14]

Answer:

a^{5}b^{3}

Step-by-step explanation:

The law of indices can be used to simplify mathematical expressions involving  arithmetical operation on variables with powers.

a^{m} x a^{n} = a^{(m+n)}

Thus, the given expression can be simplified as follows:

a³b² a²b  = a³ x a² x b² x b^{1}

               = a^{3+2} x b^{2+1}

               = a^{5}b^{3}

Thus,

a³b² a²b  = a^{5}b^{3}

7 0
2 years ago
What does s equal?pls help me plsss.
Archy [21]

Answer:

s< -7/11

Step-by-step explanation:

6 0
3 years ago
Complete the 2 column proof below given j = h and line m bisects gk
prohojiy [21]
2 Colin is j = h with us like m with bisects gk is your answer
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3 years ago
12,434.4 round nearest whole number
Nata [24]

Answer:

12,434

Step-by-step explanation:

since after the decimal point the number ranges 0-4 it will nullify but if 5-9 it will add 1 to the number before the point

7 0
2 years ago
There are 10 employees in a particular division of a company. Their salaries have a mean of 570,000, a median of $55,000,and a s
harkovskaia [24]

Answer:

a) $160,000

b) $55,000

c) $332264.804

Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

     Original Mean = $70,000

       \frac{\sum X}{n} = $70,000  ⇒ \sum X = 70,000 * 10 = $700,000

   New \sum X after change = $700,000 - $100,000 + $1,000,000 = $1600000

  Therefore, New mean = \frac{1600000}{10} = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = 20000^{2} i.e.  20000^{2} = \frac{\sum x^{2} - n*xbar }{n -1}

    Original \sum x^{2} = (20000^{2} * (10-1)) + (10 * 70,000) = $3,600,700,000

    New \sum x^{2} = $3,600,700,000 - 100,000^{2} + 1,000,000^{2} = 9.936007 * 10^{11}  

    New Variance = \frac{new\sum x^{2} - n*new xbar }{n -1} = \frac{9.936007 *10^{11}  - 10*160000 }{10 -1} = 1.103999 * 10^{11}    Therefore, standard deviation after change = \sqrt{1.103999 * 10^{11} } = $332264.804 .

7 0
3 years ago
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