Answer:
70°
Step-by-step explanation:
Connect the center of the circle with endpoints of the chord. Let the center of the circle be point O and endpoints of the chord be points A (let point A lie on the tangent line too)and B.
From the figure, central angle AOB has the measure of 220°.
Consider triangle AOB. This triangle is isosceles triangle because OA and OB are both radii. In this triangle the measure of angle AOB is 360° - 220° = 140°.
Angles OAB and OBA are angles adjacent to the base AB, so they are congruent. The sum of the measures of all interior angles in triangle is always 180°, so
m∠OAB + m∠OBA + m∠AOB = 180°
m∠OAB = m∠OBA = 1/2 (180° - 140°)
m∠OAB = 20°
Since drawn line is tangent line, then OA is perpendicular to this tangent line and
x° = 90° - 20°
x° = 70°
The answer is D. All you have to do is add all of the angles for each choice you're given. It has to add up to exactly 180, because every triangle is 180 degrees.
If you're asking how, here's an example
A standard form equation is when it is set up.
Ax + By = C.
6x + 2y = 4.
A slope-intercept form equation is when it is set up y=mx+b.
Y = - 3x + 2.
4y = -8x + 16 then divide all by 4.
y = -2x + 4 slope form.
Answer:
x = 23°
Step-by-step explanation:
Note: Complementary angles measure 90°
3x + (x - 2)° = 90°
=> 3x + x - 2° = 90°
=> 4x - 2° = 90°
Add the additive inverse of -2 to both sides of the equation
i.e 4x - 2° + 2° = 90° + 2°
=> 4x = 92°
Divide both sides of the equation by the coefficient of x which is 4
=> 4x/4 = 92°/4
x = 23°
