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Answer:
Is there supposed to be an attachment? if so please send it so I can answer your question.
Answer:
y-18=-6(x+3)
Step-by-step explanation:
y-y1=m(x-x1)
m=-6
y-18=-6(x-(-3))
y-18=-6(x+3)
Answer:
its hard to explain as a simple answer but i can explain w an example
Step-by-step explanation:
lets say the equation is 2 (3×5), rather than using pemdas and doing 3×5 fist, you take the 2 amd multiply it by the numbers in the paranthesis, so, do that snd u get 2×3 which equals 6 and then u do 2×5 which equals 10 so the equation in the end should be 6+10 which equals 16, and obviously if u use pemdas u would gey a different answer (the answer if u use pemdas is 30)
13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0
Recall the double angle identity,
sin^2(x) = (1 - cos(2x))/2
If we let x = 13pi/12, then
sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]
where we took the negative square root because we expect a negative value.
Now, because cosine has a period of 2pi, we have
cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2
Then
sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]
sin(13pi/12) = - sqrt[2 - sqrt[3]]/2