<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>Hope </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
M=30/22,5=1,33
m=25/x=1,33. ...>x=25/1,33=18,7
The answer is 31.42 since the radius is five and then you multiply it times squared and then times 3.14
[] signs mean that the number is included in the domain and () mean that the number is not included. Now,
1. [-1,5)
Because x is greater than or equal to -1 (included) but less than 5 (excluded
2. [-5,13)
When we plug in x = -1, we get the minimum value of -5, which is included because its x-value was included. The, we plug in x = 5 to find the range's maximum and this is excluded because its x-value was excluded.
3. 218
x = 6 lies in the domain of the first function so we will use it to evaluate the value of x = 6. We do this by simply substituting x into the function.
4. 12
x = 9 is included in the domain of the second function and the value of the second function at all points is 12.
5. 103
x = 10 is included in the domain of the second function so we will use it to evaluate the value of x = 10. This is done by substituting x into the equation.
6. 6th grade- go to the two columns above $600, which is about 8 students in the first column and 5 students in the 2nd. 8 + 5 = 13, so 13 students in 6th grade earned $600 or more.
7th grade- again, go to the columns above $600, which is about 7 students in the first column and about 3 in the 2nd column. 7 + 3 = 10, so 10 students in 7th grade earned $600 or more.
Do the same thing for #7, just follow the rows exactly as #6.
