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zalisa [80]
3 years ago
5

A grocery store sells a 6-pack of bottle water for $3.79, a 9-pack for $4.50, and a 12-pack for $6.89. Which package costs the l

east per bottle?
Explain your reasoning.
Show the work please.
Mathematics
1 answer:
stiks02 [169]3 years ago
5 0
Cost per bottle

6 pack is 3.79 so the cost per bottle is 3.79/6=$0.631666666666667 per bottle

9 pack is 4.50 so the cost per bottle is 4.50/9=$0.50 per bottle

12 pack is 6.89 so the cost per bottle is 6.89/12=$0.574166666667 per bottle

0.63>0.57>0.50

the one that costs the least per bottle is the 9 pack which costs $0.50 per bottle
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Determine whether f(x) = 5x+1/x and g(x)= x/ 5x+1 are inverse functions explain how you know. please explain in steps or worded
Len [333]

Hello from MrBillDoesMath!

Answer:

No


Discussion:

If the functions are inverses, then f(g(x)) = x  for appropriate x. Consider x = 1.

g(1) = 1/ (5(1) + 1) = 1/6

f(g(1)) = f (1/6) =  5(1/6) + 1/ (1/6) = 5/6 + 6 = 6 5/6   <> 1

Conclusion: f(g(1)) <> 1 so the functions are not inverses


Thank you,

MrB

7 0
4 years ago
Which of the following is another way to express the equation 8 - (-d) = 43?
Alecsey [184]
8 - (-d) = 43
8 + d = 43 <==
7 0
3 years ago
How do I solve 8×-2=-9+7×
muminat

The answer is 9/23 you simply both sides of the equation, subtract 7x from both sides, divide both sides by -23

8 0
3 years ago
Read 2 more answers
A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.
olga55 [171]
We know that:

(x-a)^2+(y-b)^2=r^2

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}

and all we have to do is solve it for a, b and r.

There will be:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\&#10;\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\&#10;\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\&#10;

From equations (II) and (III) we have:

\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}

and from (I) and (II):

\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}

Now we can easly calculate a and b:

\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}

Finally we calculate r^2:

a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}

And the equation of the circle is:

(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}
7 0
3 years ago
3,857 rounded to the nearest thousand
alekssr [168]
3,857: 

1. 3 is located in the thousands place

2. Since 8 is bigger than 3, it's telling it to go up a number (turning 3 into a 4)

Stays the Same: 1,2,3,4
Goes Up: 5,6,7,8, etc.

So 3,857 is now rounded into 4,000

7 0
3 years ago
Read 2 more answers
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