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rjkz [21]
3 years ago
14

9x⁴-3x²+1

Mathematics
1 answer:
photoshop1234 [79]3 years ago
5 0

<u>Simplifying the equation:</u>

We are given the bi-quadratic equation:

9x⁴-3x²+1

to factorise this equation, we will convert it to a quadratic equation and factor it from there

in the given equation, let x² = y

now, the equation looks like:

9y² - 3y + 1

<u>Finding the Factors </u><em><u>(in terms of y)</u></em><u>:</u>

Using the quadratic formula: x = -b±√(b²-4ac) / 2a

replacing the variables in the equation

y = [-(-3) ± √[(-3)² - 4(9)(1)]]/2(9)

y= [3 ± √-27]/18

y = (1 ± √-3 / 6)

The 2 solutions are:

y = (1 + √-3 / 6)        and     y = (1 - √-3 / 6)

<u>Finding the values of 'x':</u>

<em>Since y = x²:</em>

x² = (1 + √-3 / 6)        and     x² = (1 - √-3 / 6)

<em>taking the square root of both sides</em>

x = √(1 + √-3 / 6)        and     x = √(1 - √-3 / 6)

As we can see, the given equation has complex roots and cannot be simplified further

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In the adjoining figure, XY = XZ . YQ and ZP are the bisectors of <img src="https://tex.z-dn.net/?f=%20%5Cangle" id="TexFormula1
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See Below.

Step-by-step explanation:

Statements:                                              Reasons:

1)\, XY=XZ                                              Given

2) \text{ $ m\angle Y= m\angle Z$}                                        Isosceles Triangle Theorem

\displaystyle 3) \text{ $m\angle Y=m\angle XYQ + \angle QYZ$}                  Angle Addition

\displaystyle 4)\text{ $YQ$ bisects $\angle XYZ$}                               Given

5) \text{ $m\angle XYQ=m\angle QYZ$}                           Definition of Bisector

\displaystyle 6)\text{ $m\angle Y=2m\angle QYZ$}                               Substitution

7)\text{ $m\angle Z=m\angle XZP+m\angle PZY$}              Angle Addition

8)\text{ $ZP$ bisects $\angle XZY$}                              Given

\displaystyle 9) \text{ $m\angle XZP=m\angle PZY$ }                          Definition of Bisector

\displaystyle 10) \text{ $ m\angle Z = 2m\angle PZY $}                            Substitution

11)\text{ } 2m\angle QYZ=2m\angle PZY                    Substitution

12)\text{ }m\angle QYZ=m\angle PZY                        Division Property of Equality

13)\text{ } YZ=YZ                                         Reflexive Property

14)\text{ } \Delta YZP\cong\Delta ZYQ                             Angle-Side-Angle Congruence*

15)\text{ } YQ=ZP                                         CPCTC

*For clarification:

∠Y = ∠Z

YZ = YZ (or ZY)

∠PZY = ∠QYZ

So, Angle-Side-Angle Congruence:

ΔYZP is congruent to ΔZYQ

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