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chubhunter [2.5K]
3 years ago
9

Is 6.7 mi more precise than 6 mi?

Mathematics
2 answers:
Nataly [62]3 years ago
8 0
The answer is . . . <u><em>no</em></u> (and the reason is because you haven't provided enough information data for one to determine the precision of the distance).

"6.7 mi" you might want to argue is more precise simply because it measures this distance to the tenth of a mile

"6 mi" happens to equal "6.0 mi" which is also measured to the tenth of a mile.

Precision of a value is determined on the basis of repeatability and/or reproducibility.  If the distance is measure 3 times with results that closely match each other - that's precision.

Unfortunately, you didn't provide us with enough information, so there's no way anyone could determine whether or not this measurement is precise.

Arisa [49]3 years ago
7 0
Yes because precise means specific.
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Solve fro the Equation below:<br><br> 7+2(x-3)=-3(x+1)-4
tester [92]
7 + 2x - 6 = -3x - 3 - 4
2x + 1 = -3x - 3 - 4
2x + 1 = -3x - 7
2x + 1 + 3x = -7
5x + 1 = -7
5x = -7 - 1
5x = -8
x = -8/5.
4 0
3 years ago
Write the quadratic function in standard form.<br> f(x) = -x2 + 2x + 4<br> f(x) =
goldenfox [79]

Answer:

f(x)=-1(x-2)^2+8

Step-by-step explanation:

Given:

The quadratic function is given as:

f(x)=-x^2+2x+4

The standard form of a quadratic function is given as:

f(x)=a(x-h)^2+k, where, 'a', 'h' and 'k' are real numbers.

Now, in order to convert the given function to standard form, we use completing by  square method.

-x^2+2x=-(x^2-2x)=-[(x-2)^2-2^2]=-[(x-2)^2-4]=-(x-2)^2+4

Now, f(x)=-x^2+2x+4 can be rewritten as:

f(x)=-(x-2)^2+4+4\\f(x)=-1(x-2)^2+8

Therefore, the standard form of the function is:

f(x)=-1(x-2)^2+8

7 0
3 years ago
If g(x)=x+7 translated down 3 units
Bond [772]

Answer:

g(x)=(x+7)-3

Step-by-step explanation:

I am not so sure of what you meant for your question but I put it into an equation. it goes left 7 and 3 down.

5 0
2 years ago
Use spherical coordinates to evaluate the
kotykmax [81]

Answer:

4096π / 5

Step-by-step explanation:

∫∫∫ (x² + y² + z²) dV

In spherical coordinates, x² + y² + z² = r², and dV = r² sin φ dr dθ dφ.

E is the range 0 ≤ r ≤ 4, 0 ≤ φ ≤ π, 0 ≤ θ ≤ 2π.

∫₀ᵖⁱ∫₀²ᵖⁱ∫₀⁴ (r²) (r² sin φ dr dθ dφ)

∫₀ᵖⁱ∫₀²ᵖⁱ∫₀⁴ (r⁴ sin φ) dr dθ dφ

Evaluate the first integral.

∫₀ᵖⁱ∫₀²ᵖⁱ (⅕ r⁵ sin φ)|₀⁴ dθ dφ

∫₀ᵖⁱ∫₀²ᵖⁱ (¹⁰²⁴/₅ sin φ) dθ dφ

¹⁰²⁴/₅ ∫₀ᵖⁱ∫₀²ᵖⁱ (sin φ) dθ dφ

Evaluate the second integral.

¹⁰²⁴/₅ ∫₀ᵖⁱ (θ sin φ)|₀²ᵖⁱ dφ

¹⁰²⁴/₅ ∫₀ᵖⁱ (2π sin φ) dφ

²⁰⁴⁸/₅ π ∫₀ᵖⁱ sin φ dφ

Evaluate the third integral.

²⁰⁴⁸/₅ π (-cos φ)|₀ᵖⁱ

²⁰⁴⁸/₅ π (-cos π + cos 0)

²⁰⁴⁸/₅ π (1 + 1)

⁴⁰⁹⁶/₅ π

5 0
2 years ago
Help me im dumb and tired
Nina [5.8K]

Answer:

23/6

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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