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aleksklad [387]
2 years ago
11

5.1+2.3x=23.5..solve for x

Mathematics
2 answers:
erastovalidia [21]2 years ago
8 0

Answer:

see beleow

Step-by-step explanation:

Let's solve your equation step-by-step.

5.1+2.3x=23.5

Step 1: Simplify both sides of the equation.

2.3x+5.1=23.5

Step 2: Subtract 5.1 from both sides.

2.3x+5.1−5.1=23.5−5.1

2.3x=18.4

Step 3: Divide both sides by 2.3.

2.3x

2.3

=

18.4

2.3

x=8

Answer:

x=8

Anettt [7]2 years ago
5 0
X=8 is the correct answer
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Pls, help me I don't understand! Very urgent!!!! (I have an attachment so you know what the problem looks like)
vredina [299]

1. A pair of supplementary angles: ∠IJH and ∠HJG, ∠IJH and ∠HJG

2. A pair of complementary angles: ∠JGK and ∠KGC, ∠FGE and ∠EGD

3. A pair of vertical angles: ∠AKB and ∠KJG , ∠IJH and ∠KJG

Solution:

<em>Two angles are said to be supplementary when they add up to 180°.</em>

We know that,

Sum of the adjacent angles in a straight line = 180°

∠IJK + ∠KJG = 180°

Therefore ∠IJK and ∠KJG are supplementary angles.

∠IJH + ∠HJG = 180°

Therefore ∠IJH and ∠HJG are supplementary angles.

<em>Two angles are said to be complementary when they add up to 90°.</em>

Given ∠CGD = 90°, ∠CGJ = 90°

∠JGK + ∠KGC = ∠CGJ

∠JGK + ∠KGC = 90°

Therefore ∠JGK and ∠KGC are complementary angles.

∠FGE + ∠EGD = 90°

Therefore ∠FGE and ∠EGD are complementary angles.

<em>If two lines are intersecting, then the angles opposite to vertical point are vertical angles and they are equal.</em>

∠AKB = ∠KJG (vertically opposite)

∠IJH = ∠KJG (vertically opposite)

5 0
3 years ago
NEED HELP ASAP! Plz answer all the questions! Including the one on the picture! Will give brainlest!
xeze [42]

-2/3-(-1 1/3) =

-2/3 + 1 1/3 =

4/3 - 2/3 =

<em>2/3</em>

12 - (-5) =

12 + 5 =

<em>17</em>

-1 - (-6) =

-1 + 6 =

6 - 1 =

<em>5</em>

-3 3/8 - 7/8 =

27/8 - 7/8 =

20/8 =

2 4/8 =

<em>2</em><em> </em><em>1/2</em>

4 0
3 years ago
Read 2 more answers
A college infirmary conducted an experiment to determine the degree of relief provided by three cough remedies. Each cough remed
KiRa [710]

Answer:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed. So we can say that the 3 remedies ar approximately equally effective.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     13                      9               33

Some relief               32                   28                     27              87

Total relief                7                       9                      14               30

Total                         50                    50                    50              150

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the three remedies

H1: There is a difference in the three remedies

The level os significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*33}{150}=11

E_{2} =\frac{50*33}{150}=11

E_{3} =\frac{50*33}{150}=11

E_{4} =\frac{50*87}{150}=29

E_{5} =\frac{50*87}{150}=29

E_{6} =\frac{50*87}{150}=29

E_{7} =\frac{50*30}{150}=10

E_{8} =\frac{50*30}{150}=10

E_{9} =\frac{50*30}{150}=10

And the expected values are given by:

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No relief                    11                     11                       11               33

Some relief               29                   29                     29              87

Total relief                10                     10                     10               30

Total                         50                    50                    50              150

And now we can calculate the statistic:

\chi^2 = \frac{(11-11)^2}{11}+\frac{(13-11)^2}{11}+\frac{(9-11)^2}{11}+\frac{(32-29)^2}{29}+\frac{(28-29)^2}{29}+\frac{(27-29)^2}{29}+\frac{(7-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(14-10)^2}{10} =3.81

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(3-1)=4

And we can calculate the p value given by:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(3.81,4,TRUE)"

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed.

4 0
3 years ago
Solve for x: −2x + 5 &lt; 7 <br> Please Help Meh!! DO you LIKE to see people STRUGGLE?!?!
Arlecino [84]

x > -1


-2x+5 < 7

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Now since you divide by (-1) to get positive 2,you need to flip the sign

(-2)/(-1)= 2     2/(-1)=-2

SO

2x>-2

x > -1

To check  the solution do not replace the x by -1 because it shouls be more than -1  (You can choose 0,1,2,3....)

Example  choose x=3

-2x3+5<7

-6+5<7

-1<7

8 0
3 years ago
BRAINLIEST iF correct
mezya [45]

Answer:

See below.

Step-by-step explanation:

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You pick one at random, the chance it is NOT watermelon would be 21/28.

This is equal to 75% and 3/4

4 0
3 years ago
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