Keisha is buying a pair of jeans that are regularly

Given f(x)= 8x^{15}+6x^{8}-3x^{3}+5x^{2}, the degree is

igor_vitrenko [27]

Answer:

Step-by-step explanation:

2. Degree = 15

6 0

3 years ago

PLEASE HELP ME IN MATH IM CONFUSED

Butoxors [25]

Answer:

the second choice is correct

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{3}{4}$ x - 9 is in this form

with slope m = $\frac{3}{4}$

• Parallel lines have equal slopes, hence

y = $\frac{3}{4}$ x + c ← is the partial equation of the parallel line

To find c substitute (- 8, - 18) into the partial equation

- 18 = - 6 + c ⇒ c = - 18 + 6 = - 12

y = $\frac{3}{4}$ x - 12 ← equation of parallel line

4 0

3 years ago

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(c) $\log_2(\dfrac{64}{8})=3$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

3 years ago

Which of the binomials below is a factor of this trinomial?

Margaret [11]

$4x^2+20x-24=4(x^2+5x-6)=4(x^2+6x-x-6)\\\\=4[x(x+6)-1(x+6)]=4(x+6)(x-1)\\\\Answer:\ A)\ x-1$

6 0

2 years ago

A community hall is shape of a cuboid. The hall is 40 m long, 15 m wide and 3 m high. The community hall needs re-decorating wit

Licemer1 [7]

Total cost for tiles and paints is $924.
Step-by-step explanation:
We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.
The paint will be required for 4 walls and ceiling.
Let us find area of walls and ceiling.

Therefore, the area of walls and ceiling is 1410 square meters.
Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,

Therefore, the total painting cost is $564.
Tiles will be required for floor. Let us find the area of floor.

Given: 1m squared floor tiles costs $3. So,

Therefore, the total cost for tiles is $360.
Now let us find combined total cost of tiles and paint.

Therefore, the combined total cost of tiles and paint is $924.

3 0

2 years ago