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3 years ago

3) Our next presidential election is in

Mathematics

1 answer:

Ierofanga [76]3 years ago

6 0

Answer:121

Step-by-step explanation:

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Find the following integral. <br> Integrate x + 5/x^2 +10x +26 dx

sweet-ann [11.9K]

Given :

Polynomial , $f(x)=x+\dfrac{5}{x^2}+10x+26$ .

To Find :

Integration of f(x) .

Solution :

We know , integration of $x^n$ is :

$\int x^n \, dx = \dfrac{x^{n+1}}{n+1}+C$

( Here , is C is a constant )

Now ,

$\int f(x)\ dx=\int( x+\dfrac{5}{x^2}+10x+26)dx\\ \\ \int f(x)\ dx= \int x\ dx+\int 5x^{-2}\ dx+\int 10 x \ dx +26\ dx\\ \\ \int f(x)\ dx=\dfrac{x^2}{2}+\dfrac{5\times x^{-1}}{(-1)}+\dfrac{10x^2}{2}+26x+C\\\\ \int f(x)\ dx=\dfrac{11x^2}{2}+26x-5x^{-1}+C$

Therefore , the integration is $\dfrac{11x^2}{2}+26x-5x^{-1}+C$ .

Hence , this is the required solution .

6 0

3 years ago

Help giving brainliest

wolverine [178]

Answer:

Q1: 12.5

Q3: 16

IQR: 3.5

Step-by-step explanation:

Mean : 14.25

Median : 13.5

Mode : 13, 12

Range: 6

Minimum :12

Maximum: 18

Count n: 8

Sum: 114

Quartiles Quartiles:

Q1 --> 12.5

Q2 --> 13.5

Q3 --> 16

Interquartile

Range IQR: 3.5

Outliers: none

8 0

3 years ago

At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 18 m

Colt1911 [192]

Answer:

99.7% of customers have to wait between 8 minutes to 30 minutes for their food.

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 18 minutes

Standard Deviation, σ = 4 minutes

We are given that the distribution of amount of time is a bell shaped distribution that is a normal distribution.

Empirical Formula:

Almost all the data lies within three standard deviation from the mean for a normally distributed data.
About 68% of data lies within one standard deviation from the mean.
About 95% of data lies within two standard deviations of the mean.
About 99.7% of data lies within three standard deviation of the mean.

Thus, 99.7% of the customers have to wait:

$\mu -3\sigma = 18-3(4) = 6\\\mu +3\sigma = 18+3(4) = 30$