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Anarel [89]
3 years ago
9

What is -25.83538 times 29 to the power of three divided by 27.954?

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
4 0
I got −15,045,083.2130533
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The total amount of ribbon she had was 35 feet of ribbon.

Step-by-step explanation:

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I really do need help solving this equation
strojnjashka [21]

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D

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8 0
3 years ago
Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f
nata0808 [166]
Via Lagrange multipliers:

L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)
L_x=2xy+1+\lambda y=0
L_y=x^2+1+\lambda x=0
L_\lambda=xy-5=0

\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y
xy=5\implies y=\dfrac5x\implies\lambda=-\dfrac{11}5x

\impliesx^2+1+\left(-\dfrac{11}5x\right)x=0\implies x^2=\dfrac56\implies x=\pm\sqrt{\dfrac56}
xy=5\implies y=\pm\sqrt{30}

At these points, we get local minima of f\left(\pm\sqrt{\dfrac56},\pm\sqrt{30}\right)=\pm2\sqrt{30}.

- - -

Another way to do this is to make f(x,y) a function independent of y, which is made possible by the constraint.

xy=5\implies y=\dfrac5x
\implies f(x,y)=f\left(x,\dfrac5x\right)=F(x)=6x+\dfrac5x
\implies F'(x)=6-\dfrac5{x^2}=0\implies x=\pm\sqrt{\dfrac56}

and so on.
8 0
3 years ago
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