The impedance of transformer coil that has 600 feet is 10+j 22.62 Ω (ohms)
Explanation:
It is given that
a #22 copper wire has resistance= R= 10 Ω
                                        inductance= I=0.06 H
                                                              N=60 HZ
X= 2π * N * I
=2 * 3.14 * 60 *0.06
X=22.62 Ω
Impedance is calculated by 
Z = R + j * X
=10+ j (22.62 Ω)
Z= 10+ j 22.62 Ω
The impedance of a transformer coil that has 600 feet is  Z= 10+ j 22.62 Ω
 
        
             
        
        
        
Answer: A 
Explanation: Its one of the favorites and quite famous play.
 
        
                    
             
        
        
        
Do more than average or your level
        
                    
             
        
        
        
Figurative Language. They are both kind of the same thing but one of them compares both of the things without using like or as.