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Rashid [163]
3 years ago
9

There exist two complex numbers $c$, say $c_1$ and $c_2$, so that $3 + 2i$, $6 + i$, and $c$ form the vertices of an equilateral

triangle. Find the product $c_1 c_2$ in rectangular form.
Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer:

The answer is "\sqrt{12.5}"

Step-by-step explanation:

\to (3,2),  \ (6,1)

Distance=\sqrt{9+1}=\sqrt{10}

midpoint height =\sqrt{10+2.5}=\sqrt{12.5}

let

Gradient = \frac{1}{-3}      

Perpendicular Gradient= 3

midpoints = (4.5, 1.5)

Similar to perpendicular

Now I'll obtain the perpendicular bisector solution

An equation of the center circle(4.5,1.5) radius will be\sqrt{12.5}.

You might be interested in
Evaluate the function f(x) at the given numbers (correct to six decimal places). f(x) = x2 − 9x x2 − 8x − 9 , x = 0, −0.5, −0.9,
Lilit [14]

Answer:

See the attachment. (All results are integers, so are correct to 6 decimal places.)

Step-by-step explanation:

The function simplifies to ...

... f(x) = x(x-9)/((x+1)(x-9))

... f(x) = x/(x+1) . . . for x ≠ 9

6 0
3 years ago
PLEASE HELP ASAP! Will give BRAINLIEST! Please answer correctly!<br> No guessing!
amm1812

Answer: f(x)=567(1/3)^x

Step-by-step explanation:  

At x = 0   y = 567

at x = 1   y = 567 - 567(1/3)

at x = 2   y = 567 - 567(1/3)(1/3)

at x = 3   y = 567 - 567(1/3)(1/3)(1/3

7 0
3 years ago
The points (6,y) and (7,9) fall on a line with a slope of 5 . ​ ​What is the value of y ? ​
JulsSmile [24]

Answer:

y=4 (6,4)

Step-by-step explanation:

hope this helps!

7 0
3 years ago
Simplify: (k⁴)(k⁷)(k⁰)<br>a.k⁰<br>b.k²⁸<br>c.k¹¹<br>d.k¹²​
attashe74 [19]

Answer:

c.k¹¹

Step-by-step explanation:

Anything raised to the power of 0 is one so k^0=1

k^4k^7

Since they have the same base you can just add them

4+7=11

5 0
2 years ago
Please help ASAP!! 31 points and brainliest!
jolli1 [7]

A relation is a function if it has only One y-value for each x-value. Functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for  f(x)=4x²+2x-6

<h3>What is a function?</h3>

A relation is a function if it has only One y-value for each x-value.

The given function is

f(x)=2x²-4x+2

Put x=2/3

f(2/3)=2(2/3)²-4(2/3)+2

=2(4/9)-8/3+2

=8/9-8/3+2

=(8-24+18)/9

f(2/3)=2/9

Now f(x)=4x²+2x-6

Put x=1/4

f(1/4)=4(1/4)²+2(1/4)-6

=4/16+2/4-6

=1/4+1/2-6

= 1+2-24/4

f(1/4)==-21/4

Hence functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for  f(x)=4x²+2x-6

To learn more on Functions click:

brainly.com/question/21145944

#SPJ1

3 0
1 year ago
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