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Rashid [163]
3 years ago
9

There exist two complex numbers $c$, say $c_1$ and $c_2$, so that $3 + 2i$, $6 + i$, and $c$ form the vertices of an equilateral

triangle. Find the product $c_1 c_2$ in rectangular form.
Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer:

The answer is "\sqrt{12.5}"

Step-by-step explanation:

\to (3,2),  \ (6,1)

Distance=\sqrt{9+1}=\sqrt{10}

midpoint height =\sqrt{10+2.5}=\sqrt{12.5}

let

Gradient = \frac{1}{-3}      

Perpendicular Gradient= 3

midpoints = (4.5, 1.5)

Similar to perpendicular

Now I'll obtain the perpendicular bisector solution

An equation of the center circle(4.5,1.5) radius will be\sqrt{12.5}.

You might be interested in
Question:Find the area of he trapezoid by decomposing it into other shapes.
Ad libitum [116K]

Answer:

D) 171 cm²

Step-by-step explanation:

You don’t actually need to decompose it.  You could just do it as a trapezoid:

(15+23)/2=19

19x9=171

If you want to decompose it into 2 triangles and a rectangle:

10=15x9=135

1/2(3)(9)=13.5

1/2(5)(9)=22.5

135+13.5+22.5=171 also

8 0
3 years ago
Help me PLease<br><br><br><br> also explain how to do it
Lady bird [3.3K]

❥\Large\pmb{ \underline {\tt Answer}}

So we can only find x if other two angles of triangle is given.

In angle B as u can see boxed shape angle is there then it probably means it's a 90° angle.

We know sum of angles of triangle = 180°

{Reson :-

There's a formula to fund sum of angles of figure

  • (n-2) × 180
  • (3 -2) × 180
  • 1 × 180
  • 180°

}

Now Let's proceed

\boxed{ \rm Side_1+Side_2+Side_3 = 180\degree}

Fill all the given values

\dashrightarrow \tt 90 \degree + 55 \degree + c = 180 \degree

\\  \\

\dashrightarrow \tt 145\degree + c = 180 \degree

\\  \\

\dashrightarrow \tt  c = 180  \degree - 145\degree

\\  \\

\dashrightarrow \tt  c = 35\degree

\\  \\

Value of x = 35°

~BrainlyVIP ⸙

8 0
3 years ago
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.9 minutes and a standard deviation of 2.9
Eva8 [605]

Answer:

a) 0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) 0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes

c) 0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.9 minutes and a standard deviation of 2.9 minutes.

This means that \mu = 8.9, \sigma = 2.9

Sample of 37:

This means that n = 37, s = \frac{2.9}{\sqrt{37}}

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

320/37 = 8.64865

Sample mean below 8.64865, which is the p-value of Z when X = 8.64865. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.64865 - 8.9}{\frac{2.9}{\sqrt{37}}}

Z = -0.53

Z = -0.53 has a p-value of 0.2981

0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

275/37 = 7.4324

Sample mean above 7.4324, which is 1 subtracted by the p-value of Z when X = 7.4324. So

Z = \frac{X - \mu}{s}

Z = \frac{7.4324 - 8.9}{\frac{2.9}{\sqrt{37}}}

Z = -3.08

Z = -3.08 has a p-value of 0.001

1 - 0.001 = 0.999

0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Sample mean between 7.4324 minutes and 8.64865 minutes, which is the p-value of Z when X = 8.64865 subtracted by the p-value of Z when X = 7.4324. So

0.2981 - 0.0010 = 0.2971

0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

7 0
3 years ago
2x-17=9/x solve by factoring
aleksley [76]
X=9, - 1/2 is the answer
7 0
3 years ago
Find the ratio, pls answer quick​
Brums [2.3K]

Answer:

1) 1:10

2) 150:2

3) 1:3

4) 20hrs : 1hrs

Step-by-step explanation:

3 0
3 years ago
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