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Rashid [163]
3 years ago
9

There exist two complex numbers $c$, say $c_1$ and $c_2$, so that $3 + 2i$, $6 + i$, and $c$ form the vertices of an equilateral

triangle. Find the product $c_1 c_2$ in rectangular form.
Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer:

The answer is "\sqrt{12.5}"

Step-by-step explanation:

\to (3,2),  \ (6,1)

Distance=\sqrt{9+1}=\sqrt{10}

midpoint height =\sqrt{10+2.5}=\sqrt{12.5}

let

Gradient = \frac{1}{-3}      

Perpendicular Gradient= 3

midpoints = (4.5, 1.5)

Similar to perpendicular

Now I'll obtain the perpendicular bisector solution

An equation of the center circle(4.5,1.5) radius will be\sqrt{12.5}.

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Let x be the amount of time (in minutes) that a particular San Francisco commuter must wait for a BART train. Suppose that the d
larisa [96]

Answer:

a) P(X

P(X>14) = 1-P(X

b) P(7< X

c) We want to find a value c who satisfy this condition:

P(x

And using the cumulative distribution function we have this:

P(x

And solving for c we got:

c = 20*0.9 = 18

Step-by-step explanation:

For this case we define the random variable X as he amount of time (in minutes) that a particular San Francisco commuter must wait for a BART train, and we know that the distribution for X is given by:

X \sim Unif (a=0, b =20)

Part a

We want this probability:

P(X

And for this case we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a} = \frac{x-0}{20-0}= \frac{x}{20}

And using the cumulative distribution function we got:

P(X

For the probability P(X>14) if we use the cumulative distribution function and the complement rule we got:

P(X>14) = 1-P(X

Part b

We want this probability:

P(7< X

And using the cdf we got:

P(7< X

Part c

We want to find a value c who satisfy this condition:

P(x

And using the cumulative distribution function we have this:

P(x

And solving for c we got:

c = 20*0.9 = 18

3 0
2 years ago
F(x) = 5x – 20 find f(6), f(10), and f(20)
damaskus [11]

Answer:

f(6) = 10, f(10) = 30, f(20) = 80

Step-by-step explanation:

Plug in the values into the equation and compute. 5*6 - 20 = 10, 5*10 - 20 = 30, 5*20 - 20 = 80.

8 0
3 years ago
Please help with 11 and 12
larisa [96]
11.k>-3(4r+3)/4r-5
12.k<(2x+2)/x+3
7 0
3 years ago
A number is one more than twice the other number. their product is 36. what are the numbers​
Bad White [126]
The answer is 4 and 9 hope this helps :)
7 0
3 years ago
Read 2 more answers
I need an answer to this math problem.
tatiyna
The greatest common factor is c^2

This is because c^2 is the most that you can divide both numbers by.
7 0
2 years ago
Read 2 more answers
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