All categories

3 years ago

Solve each equation for given variable -5i -15 = 15

Mathematics

2 answers:

fredd [130]3 years ago

8 0

First you regroup the terms .
-15 - 15i = 15
Since -15i - 5i = 15 is false , there is no solution

Illusion [34]3 years ago

5 0

Answer:

i= -6

Step-by-step explanation:

-5i-15=15

if we use inverse operation here, it would be -5i=30, so i= -6

You might be interested in

Solve for b. ab+c=d. 1.b=a+c/d 2.b=a/(c-d) 3.b=(d-c)/a

amm1812

Answer:3

Step-by-step explanation:

8 0

2 years ago

Billy Bob made 16 quarts of lemon juice. How many liters of lemon juice did Billy Bob make?

pav-90 [236]

Answer:

15.14

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Jerry plans to keep up this saving pattern until he can no longer afford it.At that time, he

natta225 [31]

<h3><em>Answer: </em></h3><h3><em> I think the first answer is S(t) = 2^t - 1 .</em> </h3>

7 0

2 years ago

Nicholas has $50 to use while he is on a vacation. He decides to spend $5

Likurg_2 [28]

Answer:

days(d) = 50 ÷ 5

Explanation:

50 ÷ 5 = number of days

4 0

3 years ago

Help! If you know this can you tell me how to do it?

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

Here's how this works:

Get everything together into one fraction by finding the LCD and doing the math. The LCD is sin(x) cos(x). Multiplying that in to each term looks like this:

$[sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?$

In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:

$\frac{sin^2(x)}{sin(x)cos(x)}+\frac{cos^2(x)}{sin(x)cos(x)}=?$

Put everything over the common denominator now:

$\frac{sin^2(x)+cos^2(x)}{sin(x)cos(x)}=?$

Since $sin^2(x)+cos^2(x)=1$ , we will make that substitution:

$\frac{1}{sin(x)cos(x)}$

We could separate that fraction into 2:

$\frac{1}{sin(x)}$ × $\frac{1}{cos(x)}$

$\frac{1}{sin(x)}=csc(x)$ and $\frac{1}{cos(x)}=sec(x)$

Therefore, the simplification is

sec(x)csc(x)

5 0

3 years ago