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3 years ago

7

Please help , what’s the value of x?

1 answer:

Nataly_w [17]3 years ago

3 0

Answer:

x = 34

Step-by-step explanation:

$x=34$

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Hey, how do I apply the digital root method to division? Thanks.

REY [17]

Step-by-step explanation:

The digital root of a number is the single digit that you get by adding all of the digits of the original number together. If the result of that is multiple digits, you add those digits together, repeating the process until you get a single digit. That digit is the digital root of the original number.

example given

257520643

2+5+7+5+2+0+6+4+3

7+12+2+10+3

7+1+2+2+13

8+4+1+3

8+4+4

12+4

16

1+6=7

5 0

3 years ago

What is the lowest common denominator of 1/3 and 2/5

Citrus2011 [14]

Answer:

15

Step-by-step explanation:

3 and 5 are not common denominators so you have to find the lowest common denominator which is 15 because 3 times 5 is 15

8 0

3 years ago

Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m

Molodets [167]

Answer:

$\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1$ .

Step-by-step explanation:

We want to find $\lim_{x \to 2^-} \frac{|x-2|}{x-2}$ .

By definition:

$|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:$

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}$ .

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1)$ .

The limit of a constant is the constant.

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1$ .

8 0

3 years ago

32.17 divided by 7= i need to estimate and quotient

joja [24]

32.17/7 =

about 4.59571428571429

are there any instructions on rounding it to the nearest tenth, hundredths, etc.?

8 0

3 years ago

Jamal makes $12.00/hour and worked 9 hours today. What is his total pay? Don't forget to calculate overtime pay.

Elanso [62]

Answer:

He made $108 in 9 hours

Step-by-step explanation:

I first multiplied 12 by 9 and got 108

5 0

4 years ago

Read 2 more answers