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Flauer [41]
3 years ago
14

One number is 7 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 748 ​

, find the numbers.
Mathematics
1 answer:
baherus [9]3 years ago
3 0

Answer:

72, 504, 172

Step-by-step explanation:

Let the unknown number be denoted as "x"

The second number = 7x

And the third number = 100 + x

(x) + (7x) + (100 + x) = 748

x + 7x + x + 100 = 748

9x + 100 = 748

9x = 748- 100

9x = 648

x = 648/9

x = 72

The first number = 72

The second number = 7x = 7 × 72 = 504

The third number = 100 + x = 100 + 72 = 172

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Mnenie [13.5K]

Your drawing was much more helpful and informative than your statements in words and symbols.

I see that you want to evaluate (3/2)^2 times (8/15)^2.

You could combine these two expressions into one, as follows:

3*8

( ----------- )^2

2*15

This, in turn, can be simplified by reduction:


( 4/5 )^2. Expanded, this result gives us 16/25.


Next problem

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( 9/4 )^4 * ( 4/3 )^3

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First, focus on ( ------- ) * ( ----------- )

4^4 3^3

Now reduce 4^3 / 4^4: The end result is 1/4.

Reduce 9^4 / 3^3. To do this, rewrite that 9 as (3^2), resulting in:

3^8 / 3^3. The end result is 3^5.

Putting this expression back together, we get 3^5 / 4 (answer)

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tatuchka [14]

Answer:

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Step-by-step explanation:

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