X³+y³+z³=k, for each k from 1 to 100
1 answer:
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In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]
I'm using the program GeoGebra to get the task done of finding the roots. In this case, there are 2 roots and they are marked by the points A and B in the attachment shown
A = (1.91, 0)
B = (4.37, 0)
So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians
Answer:
Width of the pool = 15 yards
Step-by-step explanation:
Given that:
Length of diagonal of swimming pool = 29 yards
Length of the pool = 25 yards
Let,
w be the width.
This will form a right angled triangle where the diagonal will be hypotenuse.
Using Pythagorean theorem;
Taking square root on both sides
Rounding off to nearest whole number
w = 15 yards
Hence,
Width of the pool = 15 yards